The mass of NaCl needed for the reaction is 91.61 g
We'll begin by calculating the number of mole of F₂ that reacted.
- Gas constant (R) = 0.0821 atm.L/Kmol
PV = nRT
1.5 × 12 = n × 0.0821 × 280
18 = n × 22.988
Divide both side by 22.988
n = 18 / 22.988
n = 0.783 mole
Next, we shall determine the mole of NaCl needed for the reaction.
F₂ + 2NaCl —> Cl₂ + 2NaF
From the balanced equation above,
1 mole of F₂ reacted with 2 moles of NaCl.
Therefore,
0.783 mole F₂ will react with = 0.783 × 2 = 1.566 moles of NaCl.
Finally, we shall determine the mass of 1.566 moles of NaCl.
- Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
Mass = mole × molar mass
Mass of NaCl = 1.566 × 58.5
Mass of NaCl = 91.61 g
Therefore, the mass of NaCl needed for the reaction is 91.61 g
Learn more about stiochoimetry: brainly.com/question/25830314
Mercury is the only metal that is a liquid at room temperature.
your answer is A.
It is used in thermometer.
Molarity's formula is known as: Molarity(M)=moles of solute/liters solution.
In this case we are already given moles and liters so you just have to plug the numbers into the equation.
0.400 mol HCL/9.79L solution=0.040858M
If you were to use scientific notation, the answer will be: 4.1*10^-2, but otherwise, you can just use the decimals above and round appropriately as you see fit.
Answer:
CH3CH2CH2CH2CH2OH.
Explanation:
Hello.
In this case, since the vapor pressure is known to be the pressure exerted by the gaseous molecules in equilibrium with a liquid, we can infer that the higher the molecule, the lower the vapor pressure because the molecules tend to be help together more strongly and more energy is required to separate them and take them from liquid to gas.
In such a way, since CH3CH2CH2CH2CH2OH is the longest molecule (five carbon atoms) it would be more stable at liquid phase which means that it has less molecules moving to gaseous phase, which is also related with the lowest vapor pressure. Conversely, CH3CH2OH has the highest vapor pressure.
Best regards.
I believe the answer is C, n = 3, l = 3, m = 3. The magnetic quantum number, or
<span>ml</span>, can only take values that range from <span>−l</span> to <span>+l</span>, as you can see in the table above.
For option C), the angular momentum quantum number of equal to ++2<span>, which means that <span>ml</span> can have a maximum value of </span>+2<span>. Since it is given as having a value of </span>+3**, this set of quantum numbers is not a valid one.
The other three sets are valid and can correctly describe an electron.
