Question

Two electrons initially repel each other with an electric force of magnitude 2.6×10−20 N .What is the magnitude of the electric field at one electron due to the other?

Answer 1

Answer:

0.1625 N/C

Explanation:

F = Force with which electrons repel each other = $2.6\times 10^{-20}\ N$

q = Charge of electron = $1.6\times 10^{-19}\ C$

Electric field is given by

$E=\dfrac{F}{q}\\\Rightarrow E=\dfrac{2.6\times 10^{-20}}{1.6\times 10^{-19}}\\\Rightarrow E=0.1625\ N/C$

The electric field at one electron due to the other is 0.1625 N/C