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givi [52]
2 years ago
10

What is the flow rate of water in a pipe flowing full with an area of 0.3 m2 and velocity of 2.5 m/s?

Physics
1 answer:
sashaice [31]2 years ago
4 0

Answer:

0.75 m³/s

Explanation:

Applying,

Q = vA.................... Equation 1

Where Q = flow rate of the water, v = velocity of the water, A = area of the pipe.

From the question,

Given: v = 2.5 m/s, A = 0.3 m²

Substitute these values into equation 1

Q = 2.5(0.3)

Q = 0.75 m³/s

Hence the flow rate of water in the pipe is 0.75 m³/s

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A wheel initially rotating at 12 rad/s decelerates uniformly to rest in 0.4 s. If the wheel has a rotational inertia of 0.5 kg.m
Firdavs [7]

Answer:

(B) 15 N.m

Explanation:

The deceleration of the wheel is first found by using the following formula:

\alpha = \frac{\omega_f - \omega_i}{t}

where,

α = angular acceleration = ?

ωf = final angular speed = 0 rad/s

ωi = initial angular speed = 12 rad/s

t = time = 0.4 s

Therefore,

\alpha = \frac{0\ rad/s - 12\ rad/s}{0.4\ s}\\\\\alpha = -30\ rad/s^2

here, the negative sign shows deceleration.

Now, we find the torque responsible for this deceleration:

\tau = I\alpha

where,

τ = torque = ?

I = rotational inertia = 0.5 kg.m²

Therefore,

\tau = (0.5\ kg.m^2)(30\ rad/s^2)\\

τ = 15 N.m

Therefore, the correct answer is:

<u>(B) 15 N.m</u>

8 0
3 years ago
A truck is speeding up as it travels on an interstate. The truck's momentum (in kg · m/s) is proportional to the truck's speed (
muminat

Answer:

At the moment, the truck's momentum (in kg · m/s)  is 2200 times as large as the truck's speed (in m/s).

This means that as the truck travels, the truck's momentum (in kg · m/s) is always 2200 times as large as the truck's speed (in m/s).

If the truck is travelling at 16 m/s, the truck's momentum is 35200 kg · m/s.

Explanation:

From the question,

The truck's momentum (in kg · m/s) is proportional to the truck's speed (in m/s).

Let the truck's momentum be P and the truck's speed be v,

Then  we can write that

P∝v

Then,

P = kv

Where k is the proportionality constant

From the question,

At some moment the truck's momentum is 50600 kg · m/s and the truck's speed is 23 m/s,

To determine how many times the truck's speed is as large as the truck's momentum at this moment, we will divide the truck's momentum by the speed, that is

50600 ÷ 23 = 2200

Hence, at the moment, the truck's momentum (in kg · m/s)  is 2200 times as large as the truck's speed (in m/s).

Since, dividing the truck's momentum by the truck's speed gives the proportionality constant k (that is, P/v = k), then

This means that as the truck travels, the truck's momentum (in kg · m/s) is always 2200 times as large as the truck's speed (in m/s).

From

P = kv

Then, k = P/v

At a moment, P = 50600 kg · m/s and v = 23 m/s

∴ k = 50600 kg · m/s ÷ 23 m/s = 2200 kg

k = 2200 kg

To determine the truck's momentum if the truck is traveling at 16 m/s

From

P = kv

k = 2200 kg

v = 16 m/s

∴ P = 2200 kg × 16 m/s

P = 35200 kg · m/s

Hence, if the truck is travelling at 16 m/s, the truck's momentum is 35200 kg · m/s.

3 0
3 years ago
La corriente que fluye por una resistencia es
kirill [66]
Si I think the answer is lster
4 0
3 years ago
I tried the experiment of dropping candy into a liter of soda and caused a big explosion of foamy soda. Is that a physical or Ch
Aleks04 [339]

Answer:

physical change

Explanation:

its a physical change because its still soda it hasn't changed into anything else than what it already is

6 0
3 years ago
Two 3 g bullets are fired with speeds of 40 m/s and 80 m/s. what is the kinetic energy of the first bullet
Licemer1 [7]

The answer is 60. Second is 120.

8 0
2 years ago
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