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3 years ago

What is the energy of a photon with a frequency of 5 x 10^14 Hz?

Physics

1 answer:

zloy xaker [14]3 years ago

8 0

Answer:

$3.315 x 10^-19 J$

Explanation:

Using Eisten's formula, energy is a product of Plank's constant and photon frequency

E=hf

Where f represent frequency, h is Plank's constant and E is energy.

Substituting frequency with 5 x 10^14 Hz and

Planck's constant is 6.63 x 10^-34 J•s.

$E=6.63 x 10^{-34} *5 x 10^{14}=3.315x10^{-19} J$

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What was the long-term effect of the Northwest Ordinance of 1787?

victus00 [196]

Answer:

Established a government for the Northwest Territory, outlined the process for admitting a new state to the Union, and guaranteed that newly created states would be equal to the original thirteen states

Explanation:

Goooogle, so I hope this helps somewhat

Also, isn't this a History question? You put physics lol

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3 years ago

What are the fastest spinning objects known in the universe?

Sergio039 [100]

1) neuron stars

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1 year ago

An object 5.Ocm in the length is placed at a distance of 20cm in front of convex mirror

andrew-mc [135]

Answer:

Position = $\frac{60}{7}\ cm$ behind the mirror

Nature = Virtual and Erect

Size = $\frac{15}{7}\ cm$ : Diminished

Explanation:

Sign convention-Distance measured to the left of pole is negative and to the right of pole is positive.

Object distance = u = -20 cm

Focal length = f = Radius of curvature/2 = 30/2 = 15 cm

We have to use mirror formula to find image distance.

$\frac{1}{u}+\frac{1}{v}=\frac{1}{f}\\ \frac{1}{-20}+\frac{1}{v}=\frac{1}{15}\\ \frac{1}{v}=\frac{7}{60}\\v=\frac{60}{7}\ cm$

Since the image distance is positive, it is formed behind the mirror or a virtual image is formed.

Magnification = $=\frac{h_{image}}{h_{object}}=$ $-\frac{v}{u}=\frac{60}{7\times20}=\frac{3}{7}$

Height of the object = 5 cm

Height of the image = $5\times\frac{3}{7}=\frac{15}{7}\ cm$

Since the height of the image is positive and less than the size of object,it is erect and diminished.

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3 years ago

Calculate the distance the gecko covers when sprinting from rest to 2 m/s in a time of 1.5 s.

KIM [24]

Answer:

1.5 m

Explanation:

a = v/t

a = 2/1,5 = 4/3

x = 1/2 a t² + vt + x

x = 1/2 × 4/3 × 9/4 = 3/2 =1.5 m

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3 years ago

What are 5 examples of pseudoscience that can be found on the Internet?

mel-nik [20]

-- flat Earth
-- no moon landings
-- no gravity
-- chem trails
-- astrology

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3 years ago