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3 years ago

(a) Write a pair of negative integers whose difference gives 8.

Mathematics

1 answer:

elixir [45]3 years ago

7 0

(a) -2 and -10
(b) -1 and 5
(c) 1 and -4

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Three different whole numbers add up to 31.

lubasha [3.4K]

Let's find the least possibilities:

First number: 6
Second number: 8
Third number: 10

6 + 8 + 10 = 24

Now we can see that we are still missing 31 - 24 = 7.

7 can be gained by adding 3 and 4, so:

First number: 6 + 3 = 9
Second number: 8 + 4 = 12
Third number: 10

9 + 12 + 10 = 31

5 0

3 years ago

Solve this proportion 9/v = 3/2 a. {6} b. {7.3} c. {4.4} d. {1.3} What percent of 151 is 119.5? a. 129.8% b. 126.4% c. 79.1% d.

Roman55 [17]

V = ( 9*2 ) / 3 ;
v = 18 / 3 ;
v = 6 ;
a. is the right answer;

( 119.5 / 151 ) * 100 = 11950 / 151 = 79.1 ;

The percent is 79.1%;

c. is the right answer;

1 - (40/100)*1 = 1 - 2 / 5 = 3 / 5 = 0.60 ;
d. is the right answer.

6 0

3 years ago

Find the square root of the following decimal numbers.

Softa [21]

Answer:

Answer is in picture

Step-by-step explanation:

Hope it is helpful.......

5 0

3 years ago

Read 2 more answers

Solve this system of linear equations. Separate

alex41 [277]

Answer:

y = 7 and x =3

Step-by-step explanation:

use elimination method

so we gonna eliminate y first

9x = 1 - 4y

-7x = -7 + 4y

7| 9x = 1 - 4y

9| -7x = -7 + 4y

63x = 7 - 28y

-63x = -63 + 36y

add eqtn 1 to eqtn2

you will get

0 = -56 + 8y

56 = -56 + 56 + 8y

56 = 8y

56÷8 = 8y÷ 8

7 = y

also eliminate x as we have done wth y

4| 9x = 1 - 4y

4| -7x = -7 + 4y

36x = 4 - 16y

-28x = -28 + 16y

add the two equations

u will get

8x = -24 + 0

8x = -24

8x÷8 = 24÷ 8

x = 3

5 0

3 years ago

Given: Triangle ABC : triangle ADB. AB =24, AD =16 <br> Find: AC

RoseWind [281]

Answer:

Step-by-step explanation:

Given ΔABC and ΔADB, since both triangles are right angled triangles then the following are true.

From ΔADB, AB² = AD²+BD²

Given AB = 24 and AD = 16

BD² = AB² - AD²

BD² = 24²-16²

BD² = 576-256

BD² = 320

BD = $\sqrt{320}$

BD = 17.9

from ΔABC, AC² = AB²+BC²

SInce AC = AD+DC and BC² = BD² + DC² (from ΔBDC )we will have;

(AD+DC)² = AB²+ (BD² + DC²)

Given AD = 16, AB = 24 and BD = 17.9, on substituting

(16+DC)² = 24²+17.9²+ DC²

256+32DC+DC² = 24²+17.9²+ DC²

256+32DC = 24²+17.9²

32DC = 24²+17.9² - 256

32DC = 640.41

DC = $\frac{640.41}{32}$

DC = 20.01

Remember that AC = AD+DC

AC = 16+20.01

AC = 36.01

6 0

3 years ago