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2 years ago

12

An object at rest on a flat, horizontal surface explodes into two fragments, one seven times as massive as the other. the heavie

r fragment slides 6.70 m before stopping. how far does the lighter fragment slide?

1 answer:

Doss [256]2 years ago

6 0

By conservation of momentum,
Distance lighter fragment slide= 7*6.7=46.9m

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Explanation:

The given information are;

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3 years ago

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For this case we know the following info:

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We assume that we don't have melting or vaporization in the 2 substances. So we just have presence of sensible heat given by this formula:

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And for this case we know that Both A and B are at the same initial temperature when equal amounts of energy are added to them, so then we have this:

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And if we replace the formula for sensible heat we got:

$m_A c_{pA} \Delta T_A = m_B c_{pB} \Delta T_B$

And if we replace for the change of the temperature we got:

$m_A c_{pA} (T_{fA} -T_{iA}) = m_B c_{pB} (T_{fB}- T_{iB})$

And since $T_{iA}= T_{iB}= T$ we have this:

$m_A c_{pA} (T_{fA} -T) = m_B c_{pB} (T_{fB}- T)$

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d) More information is needed

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