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Klio2033 [76]
3 years ago
14

Which pair below describes isotopes of the same element? A) an atom with 6 protons and 8 neutrons - an atom with 8 protons and 6

neutrons B) an atom with 6 protons and 6 neutrons - an atom with 6 protons and 7 neutrons C) an atom with 8 protons and 8 neutrons - an atom with 7 protons and 8 neutrons D) an atom with 7 protons and 6 neutrons - an atom with 6 protons and 6 neutrons
Physics
2 answers:
iogann1982 [59]3 years ago
7 0

An isotope is an atom with a different number of neutrons than another atom of the same element. Since atoms of the same element all have the same number of protons, choice B(6pro &6neu vs. 6pro&7neu) is an example of isotopes



Otrada [13]3 years ago
4 0

Answer: B)an atom with 6 protons and 6 neutrons - an atom with 6 protons and 7 neutrons

Explanation:

Isotopes are elements which have same atomic number but different mass number.

Mass number is defined as the sum of number of protons and neutrons that are present in an atom.

Mass number = Number of protons + Number of neutrons

Atomic number is defined as the number of protons or number of electrons that are present in an atom.

Atomic number = Number of electrons = Number of protons

Thus isotopes of same element must have same number of protons and different number of neutrons.

The only combination that fulfil this criteria is : an atom with 6 protons and 6 neutrons - an atom with 6 protons and 7 neutrons

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4 0
3 years ago
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A 750-kg automobile is moving at 26.2 m/s at a height of 5.00 m above the bottom of a hill when it runs out of gasoline. The car
Kisachek [45]

To solve this problem it is necessary to apply to the concepts related to energy conservation. For this purpose we will consider potential energy and kinetic energy as the energies linked to the body. The final kinetic energy is null since everything is converted into potential energy, therefore

Potential Energy can be defined as,

PE = mgh

Kinetic Energy can be defined as,

K= \frac{1}{2} mv^2

Now for Conservation of Energy,

KE_i+PE_i = PE_f

\frac{1}{2}mv_i^2+mgh_1 = mgh_2

\frac{1}{2} (750kg) (26.2m/s)^2 + (750)(9.8)(5) = (750)(9.8)h_2

h_2 = 40.0224m

Therefore the highets position the car reaches above the bottom of the hill is 40.02m

6 0
4 years ago
What is the acceleration of a car initially traveling at -5m/s and<br> reaching -22m/s in 3s.
lozanna [386]

Answer:

a=-5.67\ m/s^2

Explanation:

Given that,

Initial velocity, u = -5 m/s

Final velocity, v = -22 m/s

Time, t = 3s

We need to find the acceleration of the car. The formula of it is given by :

Acceleration,

a=\dfrac{v-u}{t}\\\\a=\dfrac{(-22)-(-5)}{3}\\\\a=-5.67\ m/s^2

So, the acceleration of the car is -5.67\ m/s^2.

4 0
3 years ago
Write the ordered pair that represents vec yz .Then find the magnitude of vec yz Y(- 4, 12), (1, 19)
sladkih [1.3K]

Answer with Explanation:

We are given that

Y=(-4,12)

Z=(1,19)

We have to find the ordered pair which represents the vector YZ and magnitude of vector YZ.

Vector YZ=Z-Y=<1,19>-<-4,12>

Vector YZ=<5,7>

Magnitude of vector r

r=xi+yj

\mid r\mid=\sqrt{x^2+y^2}

Using the formula

\vec{YZ}=\sqrt{5^2+7^2}

\vec{YZ}=\sqrt{25+49}=\sqrt{74} units

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3 years ago
What name is given to the force on an object caused by the earth's gravitational pull?
FrozenT [24]
Acceleration due to gravity
6 0
3 years ago
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