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Elodia [21]
3 years ago
10

Explain how you could model a compressional wave using a coiled spring toy.

Physics
2 answers:
Sidana [21]3 years ago
6 0
According to one source, the answer is "Grab and pull forward and backwards lengthwise.". When executed, this creates longitudinal waves which can be observed as compression waves. Thank you for your question. Please don't hesitate to ask in Brainly your queries. 
DerKrebs [107]3 years ago
4 0
Explain how you could model a compressional wave using a coiled spring toy
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Vision is blurred if the head is vibrated at 29 Hz because the vibrations are resonant with the natural frequency of the eyeball
Likurg_2 [28]

Answer:

k = 4422.35  KN/m

Explanation:

Given that

Frequency ,f= 29 Hz

m = 7.5 g

Natural frequency ω

ω = 2 π f

We also know that for spring mass system

ω ² m =k        

k=Spring constant

So we can say that

( 2 π f)² =  m k

By putting the values

(2 x π x 29)² = 7.5 x 10⁻³  k

33167.69 = 7.5 x 10⁻³  k

k=4422.35 x  10³ N/m

k = 4422.35  KN/m

Therefore spring constant will be 4422.35  KN/m

4 0
3 years ago
We can determine the velocity of a wave when given the _______ and the wavelength.
ehidna [41]

Answer:

velocity = frequency * wavelength

Given the wavelength one must also have the frequency.

7 0
3 years ago
Windmills are used to convert wind energy into a more useful form. In most cases, there are three
sdas [7]
The kinetic energy of the wind ==> causes ==>
       the windmill to turn (mechanical energy) ==>
       which is used to turn an electric generator ==>
                      which generates electrical energy.
4 0
2 years ago
In the year 1178. five monks at Canterbury Cathedral in England observed what appeared to be an asteroid colliding with the moon
Lubov Fominskaja [6]

Answer: 1.28 sec

Explanation:

Assuming that the glow following the collision was produced instantaneously, as the light propagates in a straight line from Moon to the Earth at a constant speed, we can get the time traveled by the light applying velocity definition as follows:

V = ∆x / ∆t

Solving for ∆t, we have:

∆t = ∆x/v = ∆x/c = 3.84 108 m / 3.8 108 m/s = 1.28 sec

8 0
3 years ago
You measure a watch's hour and minute hands to be 7.4 mm and 12.1 mm long, respectively. Part A In one day, by how much does the
pychu [463]

Answer:

109.385m

Explanation:

In 1 day, the hour hand travels 2 circles, or 4π rad in angular. The distance it travels is its angle times the radius

7.4 * 4π = 93 mm

In 1 day, the minute hand travels 24*60 = 1440 circles, or 1440 * 2π = 2880π rad in angular. The distance it travels is

12.1 * 2880π = 109478 mm

So the distance traveled by the tip of the minute hand that exceed the distance traveled by the tip of the hour hand is

109478 - 93 = 109385 mm or 109.385 m

3 0
3 years ago
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