3 years ago

2.40 g of NH4Cl is added to 19.4 g of water. Calculate the molality of the solution.

1 answer:

3 0

Molality is the moles of solute per kg of solvent.

Moles of NH₄Cl = 2.4 / (14 + 4 x 1 + 35.5)
= 0.0448 mole

Molality = 0.0448 / (19.4 / 1000)
= 2.31 m

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