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OLga [1]
3 years ago
12

In which situation are both the speed and velocity of the car changing?

Physics
2 answers:
lubasha [3.4K]3 years ago
6 0
Answer is A because the speed and velocity would change. Think of it as GTA, your going 30+ miles per hour and you take a left turn, the speed and velocity would change in an instant.. 
Hope this helped.
NemiM [27]3 years ago
6 0
The answer to this question is:
<span>In which situation are both the speed and velocity of the car changing?
A) The car turns left at 5
m
s
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
If I made a mistake please feel free to tell me ^-^
</span>
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Calculate the velocity of an apple that falls freely from rest and drops for 3.5 seconds.
padilas [110]

Answer:

initial velocity(u)=0

time(t)=3.5sec

acceleration (a)=9.8m/s²

final velocity (v)=?

Explanation:

we have

v=u+at=0+9.8×3.5=34.3m/s

6 0
2 years ago
Light is incident on the left face of an isosceles prism; with an apex angle of 49o, such that the light exiting the right face
Sunny_sXe [5.5K]

Answer:

\mu = 1.645

Explanation:

By Snell's law we know at the left surface

\theta_i = 19^o

\theta_r = ?

\mu_1 = 1

\mu_2 = \mu

now we have

1 sin19 = \mu sin\theta_r

0.33 = \mu sin\theta_r

now on the other surface we know that

angle of incidence = \theta_r'

\theta_e = 90

so again we have

\mu sin\theta_r' = 1 sin90

so we have

\theta_r = sin^{-1}\frac{0.33}{\mu}

\theta_r' = sin^{-1}\frac{1}{\mu}

also we know that

\theta_r + \theta_r' = 49

sin^{-1}\frac{0.33}{\mu} + sin^{-1}\frac{1}{\mu} = 49

By solving above equation we have

\mu = 1.645

3 0
3 years ago
Read 2 more answers
Unpolarized light with an intensity of 655 W / m2 is incident on a polarizer with an unknown axis. The light then passes through
Norma-Jean [14]

Answer:

1.\theta=29.84^{0}

2.\theta=60.15^{0}

Explanation:

Polarizes axis can create two possible angles with the vertical.

first we have to find the intensity of  first polarizer

which is given as

I=\frac{I_{0} }{2}

I= \frac{655\frac{W}{M^{2} } }{2}

I=327.5\frac{W}{m^{2} }

For a smaller angle for the first polarizer:

According to Malus Law

I_{2} =I_{1} Cos^{2}(90^{0} - \theta)

I_{2} =I_{1} sin^{2}\theta

\frac{I_{2} }{I_{1} }=Sin^{2}\theta

taking square root on both sides

\sqrt{\frac{163}{327.5} } = sin\theta

\theta=Sin^{-1}(0.4977)

\theta=29.84^{0}

For a larger angle for the first polarizer:

According to Malus Law

I_{2} =I_{1} cos^{2}\theta

\frac{I_{2} }{I_{1} }=Cos^{2}\theta

taking square root on both sides

\sqrt{\frac{163}{327.5} } = cos\theta

\theta=Cos^{-1}(0.4977)

\theta=60.15^{0}

7 0
3 years ago
Soft ball,kick ball,wiffle ball??
Anvisha [2.4K]
1. No they aren’t because they all belong to different sports and are used differently
6 0
2 years ago
Read 2 more answers
Which officeholders are elected by the electoral college
NikAS [45]

Answer:Electoral Vote

Explanation:i did it before

4 0
2 years ago
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