Answer:
Characteristics outlined below
Explanation:
Anthropods, though they generally possess exoskeleton, segmented bodies and joint appendages, are divided into four (4) groups:
- <em>Tracheata</em> (breath through channels in their bodies. E.g. insects)
- Chelicerata (More than four legs, one pir of chelicerae i.e. claw or pincer. E.g. Scorpions and spiders)
- <em>Crustaceans</em> (Have a large rigid exoskeletal, without a circulatory system. E.g. Shrimps, crabs)
- <em>Trilobite</em> (extinct three-headed/lobed marine species)
Answer:
a.is the same as science
c. influences science
e. helps scientists observe fast phenomena
Explanation:
Answer is: <span>the charge of the iron in this compound is +2.
Atomic mass of iron is 55,8 g/mol.
Atomic mass of chlorine is 35,5 g/mol.
If compound is FeCl, molar mass would be 55,8 </span>g/mol + 35,5 g/mol = 91,3 g/mo, that is not correct.
If compound is FeCl₂, malar mass of compound would be:
55,8 g/mol + 2·35,5 g/mol = 126,8 g/mol, that is correct.
Oxaidation number of chlorine is -1.
Answer:
k = 2,04x10⁻⁵
Explanation:
The equilibrium of acetic acid (CH₃COOH) in water is:
CH₃COOH ⇄ CH₃COO⁻ + H⁺.
And the equilibrium constant is defined as:
k = [CH₃COO⁻] [H⁺] / [CH₃COOH] <em>(1)</em>
The equiibrium concentration of each specie if the solution of acetic acid is 0,05M is:
[CH₃COOH] = 0,05M - x
[CH₃COO⁻] = x
[H⁺] = x
<em>-Where x is the degree of reaction progress-</em>
As the pH is 3, [H⁺] = 1x10⁻³M. That means x = 1x10⁻³M
Replacing in (1):
k = (1x10⁻³)² / 0,05 - 1x10⁻³
k = 1x10⁻⁶ / 0,049
<em>k = 2,04x10⁻⁵</em>
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I hope it helps!
Answer: -
A 3.00-l flask is filled with gaseous ammonia, NH₃. the gas pressure measured at 26.0 ∘c is 1.55 atm . assuming ideal gas behavior, 3.23 grams of ammonia are in the flask
Explanation: -
Volume V = 3.00 L
Pressure P = 1.55 atm
Temperature T = 26.0 °C + 273 = 299 K
We know the value of Universal gas constant R = 0.082 L atm K−1
mol−1
We use the ideal gas equation
PV = nRT
Number of moles of Ammonia n = 
= 
= 0.19 mol
Molar mass of NH₃ = 14 x 1 + 1 x 3 = 17 g / mol
Mass of NH₃ = Molar mass of NH₃ x number of moles of NH₃
= 17 g / mol x 0.19 mol
= 3.23 g
