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marin [14]
3 years ago
7

What intermolecular forces are present in each of the substances?

Chemistry
2 answers:
Nesterboy [21]3 years ago
4 0
What intermolecular forces are present in each of the substances? CH4,C3H8,CH3F,HF, C6H5OH (dispersion forces<span>, </span>dipole-dipole forces<span>, or </span>hydrogen bonding<span>);A sample of ideal gas at room temperature occupies a volume of 34.0L at a pressure of 782torr .</span>
pochemuha3 years ago
3 0

What intermolecular forces are present in each of the substances? (1) Chloroform, CHCl3, (2)Oxygen, O2, (3)Polyethylene, CnH2n+2, and (4)Methanol, CH3OH.

<h3>Explanation: </h3>

Intermolecular forces  are the forces that mediate interaction between molecules including forces of attraction or repulsion act between molecules and other types of neighboring particles, atoms or ions. The four intermolecular forces are: Ionic bonds, Hydrogen bonding, Van der Waals dipole-dipole interactions, Van der Waals dispersion force. The characteristics are Ionic bonds > Hydrogen bonding > Van der Waals dipole-dipole interactions > Van der Waals dispersion force

An ionic bond is chemical bond type where one or more electrons are transferred from one atom to another. Hydrogen bond is attractive (dipole-dipole) interaction between an electronegative atom and a hydrogen atom bonded to another electronegative atom. Whereas Van der Waals is distance-dependent interaction between atoms or molecules. There are two kinds of Van der Waals forces: weak London Dispersion Forces and stronger dipole-dipole forces.

  • (1) Chloroform, CHCl3, are intermolecular forces that present in each of the substances
  • (1) Chloroform, CHCl3: Dipole-dipole intermolecular forces are most important.
  • (2)Oxygen, O2: London dispersion forces are most important.
  • (3)Polyethylene, CnH2n+2: London dispersion forces are most important.
  • (4)Methanol, CH3OH: Dipole-dipole intermolecular forces and hydrogen bounds are important

Learn more about  intermolecular forces brainly.com/question/1978870

#LearnWithBrainly

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Answer:

If you mix equal amounts of a strong acid and a strong base, the two chemicals essentially cancel each other out and produce a salt and water. Mixing equal amounts of a strong acid with a strong base also produces a neutral pH (pH = 7) solution.

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Which of the following is correct for adsorption theory of Heterogeneous catalysis? Statement-I : This theory explains why the c
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The correct answer is - Statement I is true, Statement-II is false.

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Chlorine is used to disinfect swimming pools. the accepted concentration for this purpose is 1.00 ppm chlorine, or 1.00 g of chl
frez [133]

The accepted concentration of chlorine is 1.00 ppm that is 1 gram of chlorine per million of water.

The volume of water is 2.29\times 10^{4} gal.

Since, 1 gal= 3785.41 mL

Thus, 2.29\times 10^{4} gal=2.29\times 10^{4}\times 3785.41 mL=8.66\times 10^{7}mL

Density of water is 1 g/mL thus, mass of water will be 8.66\times 10^{7}g.

Since, 1 grams of chlorine →10^{6} grams of water.

1 g of water →10^{-6} g of chlorine and,

8.66\times 10^{7}g of water →86.6 g of chlorine

Since, the solution is 9% chlorine by mass, the volume of solution will be:

V=\frac{100}{9}\times 86.6 mL=9.62\times 10^{2} mL

Thus, volume of chlorine solution is 9.62\times 10^{2} mL.

6 0
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A mbxture of iron and sulfur can be separated by attracting the Iron particles with a magnet. If the iron and sulfur mixture is
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Bob measured out 1.60 grams of sodium. He calculates that 1.60 g of
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Answer:

84.8%

Explanation:

Step 1: Given data

Bob measured out 1.60 g of Na. He forms NaCl according to the following equation.

Na + 1/2 Cl₂ ⇒ NaCl

According to this equation, he calculates that 1.60 g of sodium should produce 4.07 g of NaCl, which is the theoretical yield. However, he carries out the experiment and only makes 3.45 g of NaCl, which is the real yield.

Step 2: Calculate the percent yield.

We will use the following expression.

%yield = real yield / theoretical yield × 100%

%yield = 3.45 g / 4.07 g × 100% = 84.8%

6 0
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