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3 years ago

What intermolecular forces are present in each of the substances?

2 answers:

4 0

What intermolecular forces are present in each of the substances? CH4,C3H8,CH3F,HF, C6H5OH (dispersion forces, dipole-dipole forces, or hydrogen bonding);A sample of ideal gas at room temperature occupies a volume of 34.0L at a pressure of 782torr .

pochemuha3 years ago

3 0

What intermolecular forces are present in each of the substances? (1) Chloroform, CHCl3, (2)Oxygen, O2, (3)Polyethylene, CnH2n+2, and (4)Methanol, CH3OH.

<h3>Explanation: </h3>

Intermolecular forces are the forces that mediate interaction between molecules including forces of attraction or repulsion act between molecules and other types of neighboring particles, atoms or ions. The four intermolecular forces are: Ionic bonds, Hydrogen bonding, Van der Waals dipole-dipole interactions, Van der Waals dispersion force. The characteristics are Ionic bonds > Hydrogen bonding > Van der Waals dipole-dipole interactions > Van der Waals dispersion force

An ionic bond is chemical bond type where one or more electrons are transferred from one atom to another. Hydrogen bond is attractive (dipole-dipole) interaction between an electronegative atom and a hydrogen atom bonded to another electronegative atom. Whereas Van der Waals is distance-dependent interaction between atoms or molecules. There are two kinds of Van der Waals forces: weak London Dispersion Forces and stronger dipole-dipole forces.

(1) Chloroform, CHCl3, are intermolecular forces that present in each of the substances
(1) Chloroform, CHCl3: Dipole-dipole intermolecular forces are most important.
(2)Oxygen, O2: London dispersion forces are most important.
(3)Polyethylene, CnH2n+2: London dispersion forces are most important.
(4)Methanol, CH3OH: Dipole-dipole intermolecular forces and hydrogen bounds are important

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Iupac name of h3C-C-Ch2-ch3

pshichka [43]

Answer:

The IUPAC name of given compound is 3−5−ethyl−5−−3−methylheptane. Explanation: The parental chain is of 7 carbons with single bonds hence it is heptane. Two substituents ethyl and methyl group are attached from an equal distance. Hence according to the alphabetical order preference, counting starts from carbon which is close to an ethyl group.

8 0

3 years ago

The equation for density, d, is

ss7ja [257]

Answer: The density of substance is $3.38g/cm^3$

Explanation:

To calculate density of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

We are given:

Mass of substance = 61.6 g

Volume of substance = $18.2cm^3$

Putting values in above equation, we get:

$\text{Density of substance}=\frac{61.6g}{18.2cm^3}\\\\\text{Density of substance}=3.38g/cm^3$

Hence, the density of substance is $3.38g/cm^3$

8 0

3 years ago

Which element of the periodic table is named after the moon

Troyanec [42]

Answer:

The answer to your question is Selenium

Explanation:

The origin of the names of the elements comes from different origins

For example

Sanskrit words. 14 elements have roots from this language

Planets, 4 elements took their names from the planets.

Greek, 42 elements took their names from these languages

The name of Selenium comes from the greek that means moon.

8 0

3 years ago

In the following reaction, what is the quantity of heat (in kJ) released when 5.87 moles of CH₄ are burned?

IRISSAK [1]

Taking into account the definition of enthalpy of a chemical reaction, the quantity of heat released when 5.87 moles of CH₄ are burned is 4,707.74 kJ.

The enthalpy of a chemical reaction as the heat absorbed or released in a chemical reaction when it occurs at constant pressure. That is, the heat of reaction is the energy that is released or absorbed when chemicals are transformed into a chemical reaction.

The enthalpy is an extensive property, that is, it depends on the amount of matter present.

In this case, the balanced reaction is:

CH₄ (g) + 2 O₂ (g) → CO₂ (g) + 2 H₂O(g)

and the enthalpy reaction ∆H° has a value of -802 kJ/mol.

This equation indicates that when 1 mole of CH₄ reacts with 2 moles of O2, 802 kJ of heat is released.

When 5.87 moles of CH₄ are burned, then you can apply the following rule of three: if 1 mole of CH₄ releases 802 kJ of heat, 5.87 moles of CH₄ releases how much heat?

$heat=\frac{5.87 molesof CH_{4}x802 kJ}{1 mol of CH_{4} }$

heat= 4,707.74 kJ

Finally, the quantity of heat released when 5.87 moles of CH₄ are burned is 4,707.74 kJ.

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5 0

3 years ago

An aqueous solution contains 0.100 m naoh at 25.0 °c. the ph of the solution is ________.

ikadub [295]

Recall; pH + pOH = 14
In this case [OH-] =0.100 m
therefore;
pOH = -LOG[OH-]
= - Log (0.100)
= 1.00
Therefore; the pOH is 1.00
And since, pH +pOH = 14
Then pH = 14-pOH
= 14 -1
= 13
Thus the pH is 13.00

7 0

3 years ago