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3 years ago

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3. Atmospheric pressure is often given in units of millimeters of mercury. This refers to the height of a mercury column above t

he mercury's surface at the base of a barometer . The force exerted by the atmosphere on the surface of the mercury in the reservoir equals the weight of the mercury in the column . If the mercury column extends 760 mm above the mercury's surface in the reservoir , what is the atmosphere's pressure over the mercury ? Use 13.6*10^ 3 kg/m^ 3 for the density of mercury

1 answer:

gregori [183]3 years ago

6 0

Answer:

101397.16 pa

Explanation:

The pressure recorded will be equal to pgh

Where p = density of mercury = 13.6x10^3 kg/m^ 3

g = acceleration due to gravity 9.81 m/s^2

h = height of mercury in the column = 760 mm = 760x10^-3 m

Pressure = 13.6x10^3 x 9.81 x 760x10^-3 = 101397.16 pa

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