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Tamiku [17]
3 years ago
5

What is the molarity of a solution made by dissolving 14.8 g of ammonium hydroxide NH4OH, in enough water to make 250.0 mL of so

lution
Chemistry
1 answer:
kicyunya [14]3 years ago
6 0

Answer:

Molarity= 1.69M

Explanation:

m= 14.8, Mm= 35, V= 0.25dm3, C= ?

Moles = m/M= C×V

Substitute and Simplify

m/M= C×V

14.8/35= C×0.25

C= 1.69M

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Give the electron configurations for the elements given. use the noble gas core preceding for the inner electrons.
Umnica [9.8K]
Noble Gas Cores have following electronic configuration

He  =  1s²
Ne  =  [He] 2s², 2p⁶
Ar  =   [Ne] 3s², 3p⁶
Kr  =   [Ar] 4s², 4p⁶
Xe  =  [Kr] 5s², 5p⁶

Now solving for question elements,

Germanium = Ge  =  [Ar] 3d¹⁰, 4s², 4p²

Nickle = Ni  =  [Ar] 3d¹⁰, 4s²

Tunsten = W  =  [Xe] 4f¹⁴, 5d⁴, 6s²

Titanium = Ti  =  [Ar] 3d², 4s²

Iron = Fe  =  [Ar] 3d⁶, 4s²

Zinc = Zn  =  [Ar] 3d¹⁰, 4s²
6 0
3 years ago
How many subshells in 4s
anyanavicka [17]

Answer:

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Explanation:

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3 0
2 years ago
What mass of NaF must be mixed with 25ml of water to create a 3.5% by mass solution
viva [34]

Answer:

0.91 g NaF

Explanation:

Mass percentage is one way of representing the concentration of an element in a compound or a component in a mixture. Mass percentage is calculated as the mass of a component divided by the total mass of the mixture, multiplied by 100%.

Let mass of NaF = x g

∴ mass percent = mass of NaF / mass of total mixture *100

3.5 = (x/ x + 25) * 100

∴ x = 0.91 g

7 0
3 years ago
Read 2 more answers
Someone please answer i’ll give you brainly.
lina2011 [118]
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4 0
3 years ago
[50 Points] In the experiment below, Beaker 1 contains 12.0 M HCl. Each subsequent beaker is diluted by 50%. What is the [OH-] i
Sidana [21]

Answer:

2.67x10⁻¹⁴M = [OH-]

Explanation:

To solve this question we need first to find the HCl concentration of the beaker 6. Then, using:

Kw = [OH-][H+]

<em>Where Kw = 1x10⁻¹⁴</em>

<em>[OH-] is our incognite</em>

<em>[H+] is = [HCl]</em>

<em />

Beaker 2 = 12.0M / 2 = 6.0M

Beaker 3 = 6.0M / 2 = 3.0M

Beaker 4 = 3.0M / 2 = 1.5M

Beaker 5 = 1.5M / 2 = 0.75M

Beaker 6 = 0.75M / 2 = 0.375M

HCl = 0.375M = [H+]

1x10⁻¹⁴ / [H+] = [OH-]

1x10⁻¹⁴ / 0.375M = 2.67x10⁻¹⁴M

<h3>2.67x10⁻¹⁴M = [OH-]</h3>
5 0
3 years ago
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