mass of pentane : = 30.303 g
moles of Al₂(CO₃)₃ : = 0.147
<h3>Further explanation</h3>
Given
1. Reaction
C₅H₁₂+8O₂→6H₂O+5CO₂.
45.3 g water
2. 2AlCl₃ + 3MgCO₃ → Al₂(CO₃)₃ + 3MgCl₂
37.2 MgCO₃
Required
mass of pentane
moles of Al₂(CO₃)₃
Solution
1. mol water = 45.3 : 18 g/mol = 2.52
From equation, mol ratio of C₅H₁₂ : H₂O = 1 : 6, so mol pentane :
= 1/6 x mol H₂O
= 1/6 x 2.52
= 0.42
Mass pentane :
= mol x MW
= 0.42 x 72.15 g/mol
= 30.303 g
2. mol MgCO₃ : 37.2 : 84,3139 g/mol = 0.44
mol Al₂(CO₃)₃ :
= 1/3 x mol MgCO₃
= 1/3 x 0.44
= 0.147
Answer:
X has 9 Electrons, 9 Protons and 10 Neutrons
X is Fluorine
Explanation:
19 in X is Nucleon number
So, if you minus 19 by 9 down there (which is proton number) you'll get 10 (Neutron number).
Now, Proton = Electron. That's why Electron is 9 too. I figured that X is Fluorine bcuz it has 9 Electrons. If you venture around in the periodic table, fluorine is the ninth element innit.
hope this helps ya ＼(^o^)／
A test tube of zinc oxide
Answer:
True
Explanation:
It is true that every element in the periodic table follows the Aufbau's principle.
The principle states that "the sublevels with lower energies are filled up before those with higher energies".
- Sublevels do not fill up in numerical order.
- This is true when writing the electronic configuration of all atoms on the periodic table.
Answer:
16 °C
Explanation:
Step 1: Given data
- Provided heat (Q): 811.68 J
- Mass of the metal (m): 95 g
- Specific heat capacity of the metal (c): 0.534 J/g.°C
Step 2: Calculate the temperature change (ΔT) experienced by the metal
We will use the following expression.
Q = c × m × ΔT
ΔT = Q/c × m
ΔT = 811.68 J/(0.534 J/g.°C) × 95 g = 16 °C
