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TEA [102]
3 years ago
14

A DNA sample and a plasmid with the ampR and lacZ(for the enzyme beta-galactosidase) genes are treated with Pstl with the goal o

f making recombinant DNA molecules. the lacZ gene is placed in the cloning region so that it is disrupted by DNA inserts. Put the remaining steps for this process in the right order. NOT ALL statements will be used! The first step has already been given to you.
step options: -all the fragments have the sticky ends 5'-CTGCAG-3'
-cells containing the recombinant plasmid are grown in a medium with
ampicillin and x-gal(a galactose derivative)
-blue colonies that survive on the culture medium contain the
recombinant plasmid
-all the fragments have identical sticky ends: 5'-TGCA-3'
-colonies containing the recombinant plasmid can be removed from the
culture medium and grown
-DNA ligase joins the sticky ends of the DNA sample and the plasmid
-white colonies that survive on the culture medium are identified as
having the recombinant plasmid
step 1) DNA is treated with restriction enzyme
step 2)
step 3)
step 4)
step 5)
step 6)
Chemistry
1 answer:
solong [7]3 years ago
3 0

Answer:

Explanation:

The main aim of this experiment is to correctly identify the sequential steps needed for making recombinant DNA molecules.

The first step is given as:

DNA is treated with restriction enzyme

The remaining steps in order are:

\text{-all the fragments have identical sticky ends: 5'-TGCA-3'}

\text{-DNA ligase joins the sticky ends of the DNA sample and the plasmid}

\text{-cells containing the recombinant plasmid are grown in a medium with}

\text{ampicillin and x-gal(a galactose derivative)}

\text{-white colonies that survive on the culture medium are identified as}

\text{having the recombinant plasmid}

\text{-colonies containing the recombinant plasmid can be removed from the}

\text{culture medium and grown}

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A metallic bond since both are pure metals but are not ionic



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3 years ago
Draw the structure for cis-2,3-dibromo-2-hexene.
padilas [110]
First, draw the 2-hexene. Th is is a molecule of six carbons with a double bond in the second carbon:

      CH3 - CH = CH2 - CH2 - CH2 - CH3

Secong, put one Br on the second carbon and one Br on the third carbon:

    CH3 - CBr = CBr - CH2 - CH2 - CH3

Third, cis means that the two Br are placed in opposed positions, this is drawn with one Br up and the other down. So, you need to represent the position of the Br in the space:


      H   Br          H     H      H
       |    |             |       |       |
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       |           |      |       |       |
      H          Br   H     H      H

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4 0
3 years ago
Read 2 more answers
Helium gas diffuses 4 times as fast as an unknown gas. What is relative molecular mass of the gas​
Inessa05 [86]

The relative molecular mass of the gas​ : 64 g/mol

<h3>Further explanation</h3>

Given

Helium rate = 4x an unknown gas

Required

The relative molecular mass of the gas​

Solution

Graham's Law

\tt \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

r₁=4 x r₂

r₁ = Helium rate

r₂ = unknown gas rate

M₁= relative molecular mass of Helium = 4 g/mol

M₂ = relative molecular mass of the gas​

Input the value :

\tt \dfrac{4r_2}{r_2}=\sqrt{\dfrac{M_2}{4} }\\\\16=\dfrac{M_2}{4}\\\\M_2=64~g/mol

7 0
2 years ago
If the mass percentage composition of a compound is 72.1% Mn and 27.9% O, its empirical formula is
mojhsa [17]

Answer:

MnO- Manganese Oxide

Explanation:

Empirical formula: This is the formula that shows the ratio of elements

present in a  

compound.

   

How to determine Empirical formula

1. First arrange the symbols of the elements present in the compound

alphabetically to  determine the real empirical formula. Although, there

are exceptions to this rule, E.g H2So4

2. Divide the percentage composition by the mass number.

3. Then divide through by the smallest number.

4. The resulting answer is the ratio attached to the elements present in

a compound.

           

                                                                              Mn                         O    

                         

% composition                                                      72.1                      27.9    

                       

Divide by mass number                                       54.94                     16  

                                 

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Divide by the smallest number                         1.31                      1.31                          

                                                                               1                    1.3

                                                 

The resulting ratio is 1:1

 

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8 0
3 years ago
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Mama L [17]

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3) The concentration of product increases.

This will happen when we add reactants to a chemical reaction. According to  Le-Chatelier's principle, when we increase the concentration of reactants, the equilibrium will shift in the direction where this effect is minimal. Hence, the reaction will be in the forward direction which means that the concentration of product will increase.

4) The concentration of products decreases.

This will happen when we remove reactants from a chemical reaction. According to  Le-Chatelier's principle, when we decrease the concentration of reactants, the equilibrium will shift in the direction where this effect is minimal. Hence, the reaction will be in the reverse direction which means that the concentration of reactants will increase or concentration of products will decrease.

3 0
3 years ago
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