t = d/v = 510:340 = 1,5 secunde
1,4 secunde, deci
t2 = 1,5 - 1,4 = 0,1 secunde
v2 = distanta/timp = 510 metri / 0,1secunde
= <span>5100 metri / secunda</span>
<span>hope it helps</span>
Answer:
Displacement of Mr. Llama: Option D. 0 miles.
Explanation:
The magnitude of the displacement of an object is equal to the distance between its final position and its initial position. In other words, as long as the initial and final positions of the object stay unchanged, the path that this object took will not affect its displacement.
For Mr. Llama:
- Final position: Mr. Llama's house;
- Initial position: Mr. Llama's house.
The distance between the final and initial position of Mr. Llama is equal to zero. As a result, the magnitude of Mr. Llama's displacement in the entire process will also be equal to zero.
Answer:
Explanation:
Given
Wooden board is pivoted at center and
Older child of mass
is sitting at a distance of L from center
if two child of mass
is sitting at a distance
and
(say) from pivot then net torque about pivot is zero
i.e.

as 
Therefore



Therefore another child is sitting at a distance of 
Answer:
diagram: see image, x-component: 84.3 N, acceleration: 4.38 m/s^2
Explanation:
(see image for further explanation)