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stellarik [79]
2 years ago
5

Suppose that, while lying on a beach near the equator of a far-off planet watching the sun set over a calm ocean, you start a st

opwatch just as the top of the sun disappears. You then stand, elevating your eyes by a height H = 1.43 m, and stop the watch when the top of the sun again disappears. If the elapsed time is it = 11.9 s, what is the radius r of the planet to two significant figures? Notice that duration of a solar day at the far-off planet is the same that is on Earth.

Physics
1 answer:
zubka84 [21]2 years ago
6 0

Answer:

R=3818Km

Explanation:

Take a look at the picture. Point A is when you start the stopwatch. Then you stand, the planet rotates an angle α and you are standing at point B.

Since you travel 2π radians in 24H, the angle can be calculated as:

\alpha =\frac{2*\pi *t}{24H}  t being expressed in hours.

\alpha =\frac{2*\pi *11.9s*1H/3600s}{24H}=0.000865rad

From the triangle formed by A,B and the center of the planet, we know that:

cos(\alpha )=\frac{r}{r+H}  Solving for r, we get:

r=\frac{H*cos(\alpha) }{1-cos(\alpha) } =3818Km

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Answer:

To write the general formula for an acid, we fix one atom which is hydrogen because this atom is common to all the acids. General formula for acid is written by HX. where H represents Hydrogen atom.

Explanation:

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Explain why ventilation is very important if there is risk of exposure to random gas in your home school
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2 years ago
A diver stands on a diving platform 10.0 m above the surface of a pool and leaps upward with an initial speed of 2.5 m/s. how fa
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2 years ago
this stationary wave is what we call the first harmonic of the first normal mode of the system. in units of l, the length of the
pentagon [3]

First harmonic of a closed pipe is determined as velocity, v, to four times length (4L), F₀ v/4L.

<h3>First harmonic of a closed pipe</h3>

The first harmonic of a closed pipe is the fundamental frequency of the closed of the closed pipe.

L = λ/4

where;

  • L is the length of the pipe
  • λ is the wavelength of sound

λ = 4L

But, v = F₀λ

v = F₀(4L)

F₀ = v/4L

where;

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Thus, first harmonic of a closed pipe is determined as velocity, v, to four times length (4L), F₀ v/4L.

Learn more about fundamental frequency here:  brainly.com/question/1967686

#SPJ11

<h3 />
6 0
1 year ago
A typical cell phone charger is rated to transfer a maximum of 1.0 Coulomb of charge per second. Calculate the maximum number of
Alexandra [31]

Answer:

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Solution:

As per the question:

Maximum rate of transfer of charge, I = 1.0 C/s

Time, t = 1.0 h = 3600 s

Rate of transfer of charge is current, I

Also,

I = \frac{Q}{t}

Q = ne

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Thus

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Thus the charge flow in 1. 0 h:

Q = 1.0\times 3600 = 3600\ C

Maximum number of electrons, n is given by:

n = \frac{Q}{e}

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Thus

n = \frac{3600}{1.6\times 10^{- 19}} = 2.25\times 10^{22}

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