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4 years ago

Which is an example of a primitive plant?

Physics

1 answer:

ludmilkaskok [199]4 years ago

4 0

Answer:

Non-flowering plants like mosses, horsetails, ferns, clubmosses, ginkgos, and cycads

Explanation:

Mark me brainliest plz

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A plan has a mass of 2000kg and is traveling 100 meters above the ground. What is the planes potential Energy

victus00 [196]

Answer:

2000000j

Explanation:

m*g*h

2000*100*10

=2000000

6 0

3 years ago

3–101 It is estimated that 90 percent of an iceberg’s volume is below the surface, while only 10 percent is visible above the su

Artist 52 [7]

Answer:

The density of iceberg upper water and under water are 102.5 kg/m³ and 922.5 kg/m³

Explanation:

Given that,

Volume of seawater = 90 % of Volume of iceberg

Volume of visible surface = 10 %

Density of seawater = 1025 kg/m³

We need to calculate the density of the iceberg

Using equilibrium condition

$W_{I}=F_{B}$

$\rho_{I}\times V_{I}\times g= \rho_{w}\timesV_{w}\times g$

Put the value into the formula

$\rho_{I}\times V_{I}\times g=\rho_{w}\times0.9V_{I}\times g$

$\rho_{I}=1025\times0.9$

$\rho_{I}=922.5kg/m^3$

We need to calculate the density of the iceberg

Using equilibrium condition

$W_{I}=F_{B}$

$\rho_{I}\times V_{I}\times g= \rho_{w}\timesV_{w}\times g$

Put the value into the formula

$\rho_{I}\times V_{I}\times g=\rho_{w}\times0.1V_{I}\times g$

$\rho_{I}=1025\times0.1$

$\rho_{I}=102.5\ kg/m^3$

Hence, The density of iceberg upper water and under water are 102.5 kg/m³ and 922.5 kg/m³

5 0

3 years ago

What is photosynthesis, food chain, evaporation and passive smokers?

navik [9.2K]

Answer:

Photosynthesis: the process where plants convert light energy into sugar, for food

Food chain: a series of organisms showing which organisms eat each other

Explanation:

7 0

3 years ago

An object's constant acceleration is south at 3.00 m/s2. at t = 0, its velocity is 30.0 m/s west. when will the magnitude of the

nydimaria [60]

The answer is in attachment.

8 0

4 years ago

A basketball referee tosses the ball straight up for the starting tip-off. At what velocity (in m/s) must a basket ball player l

mamaluj [8]

Answer:4.93 m/s

Explanation:

Given

height to reach is (h )1.24 m

here Let initial velocity is u

using equation of motion

$v^2-u^2=2ah$

here Final Velocity v=0

a=acceleration due to gravity

$0-u^2=2\left ( -g\right )h$

$u=\sqrt{2gh}$

$u=\sqrt{2\times 9.81\times 1.24}$

$u=\sqrt{24.328}$

u=4.93 m/s

7 0

4 years ago