The final velocity of the red barge in the collision elastic is 0.311 m/s when it collides with blue barge pf mass 1000000 kg.
Final velocity(v3) of the red barge is calculated by following formula
m1×v1+ m2×v2= (m1+m2)v3
Substituting the value of m1= 150000 kg, v1= 0.25 m/s, m2= 1000000 kg, v2= 0.32 m/s
150000 × 0.25+ 1000000×0.32= (150000+1000000)×v3
37500+ 320000= 1150000×v3
357500= 1150000×v3
v3= 0.311 m/s
<h3>What is elastic collision velocity? </h3>
- The velocity of the target particle after a head-on elastic impact in which the projectile is significantly more massive than the target will be roughly double that of the projectile, but the projectile velocity will remain virtually unaltered.
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Answer:
Explanation:
Use the velocity formula to solve
In this question, you are given velocity 
, and you are given a distance, 
. Time in this question is what you'll need to find.
Start by rearranging the velocity formula, to isolate for t.
Start by multiplying both sides by t
Then divide both sides by v.
Now that you've isolated for time, sub in your values and calculate.
Answer:
by moving your hands up and down your we're creating transverse wave which travel in a right angle shape towards your friend
First write down all your known variables:
vi = 25m/s
a = 7.0m/s^2
t = 6.0s
vf = ?
Then choose the kinematic equation that relates all the variables and solve for the unknown variable:
vf = vi + at
vf = (25) + (7.0)(6.0)
vf = 67m/s
The final velocity of the motorcycle is 67m/s.
