All categories

4 years ago

Which question about the discovery of the earth revolving around the sun could be best answered using scientific inquiry

1 answer:

8 0

AAaaahh yes, T'was that a lovely chap by the name of Copernicus, has discovered us a little secret, well. why dont you share?

Copernicus: well uh, i'm a bit shy

ME: who a gives a flying *bleep* about your feelings man! just man up an discover the earth's rotation already!

You might be interested in

What is the number “4” in SiCl4? a subscript a coefficient a product a reactant

Svetlanka [38]

Answer: 4 is the subscript in $SiCl_{4}$ .

Explanation:

We know that,

Subscript: The number of atom present in a given compound.

In $SiCl_{4}$ , 4 represents the number of chlorine atom in 1 mole of Silicon tetra chloride.

Coefficient: Number of atom which is used in reaction.

For example: In $3SiCl_{4}$ , 3 is the coefficient of silicon tetra chloride.

A Product : In the balance equation, right hand side is called product.

A reactant : In the balance equation, left hand side is called reactant.

For example: the balance equation is

$2Mg+O_{2}\rightarrow 2MgO$

In this equation, $2Mg+O_{2}$ is the reactants and $2MgO$ is products.

Hence, 4 is the subscript in $SiCl_{4}$ .

4 0

3 years ago

Read 2 more answers

Two men standing on the same side of wall and at the same distance from It, such that they are 4oom apart when one fires a gun t

Mamont248 [21]

Answer:

1. 571.43m/s

2. 142.9m and 342.9m

Explanation:

1.Take the difference in time.

1.2-0.7=0.7 seconds

Take the distance between them and divide with differnce in time.

400÷0.7=571.43 seconds.

2.Take the time of the two men and divide by two.

0.5÷2= 0.25 secs

1.2÷2= 0.6 secs

multiply each with the velocity.

0.25×571.43=142.9m

0.6×571.43=342.9m

8 0

2 years ago

An electron is moving through an (almost) empty universe at a speed of 628 km,/s toward the only other object in the universe —

sattari [20]

Answer:

r = 2,026 10⁹ m and T = 2.027 10⁴ s

Explanation:

For this exercise let's use Newton's second law

F = m a

where the force is electric

F = $k \frac{q_1q_2}{r^2}$

Acceleration is centripetal

a = v² / r

we substitute

$k \frac{q_1q_2}{r^2} = m \frac{v^2}{r}$

r = $k \frac{q_1q_2}{m \ v^2}$ (1)

let's look for the charge in the insulating sphere

ρ = q₂ / V

q₂ = ρ V

the volume of the sphere is

v = 4/3 π r³

we substitute

q₂ = ρ $\frac{4}{3}$ π r³

q₂ = 3 10⁻⁹ $\frac{4}{3}$ π 4³

q₂ = 8.04 10⁻⁷ C

let's calculate the radius with equation 1

r = 9 10⁹ 1.6 10⁻¹⁹ 8.04 10⁻⁷ /(9.1 10⁻³¹ 628 10³)

r = 2,026 10⁹ m

this is the radius of the electron orbit around the charged sphere.

Since the orbit is circulating, the speed (speed modulus) is constant, we can use the uniform motion ratio

v = x / t

the distance traveled in a circle is

x = 2π r

In this case, time is the period

v = 2π r /T

T = 2π r /v

let's calculate

T = 2π 2,026 10⁹/628 103

T = 2.027 10⁴ s

4 0

3 years ago

A vehicle ___________ occurs when the driver begins to back up and is unaware that a person is behind the vehicle.

jeka94

I don't know accident?

6 0

4 years ago

Read 2 more answers

An object propelled upwards with an acceleration of 2.0 m / s ^ 2 is launched from rest. After 6 seconds the fuel runs out. Dete

dezoksy [38]

Answer:43.34 m

Explanation:

Given

acceleration(a) $=2 m/s^2$

Initial Velocity(u)=0 m/s

After 6 s fuel runs out

Velocity after 6 s

v=u+at

$v=0+2\times 6=12 m/s$

After this object will start moving under gravity

height reached in first 6 s

$s=ut+\frac{at^2}{2}$

$s=0+\frac{2\times 6^2}{2}$

s=36 m

After fuel run out distance traveled in upward direction is

$v^2-u^2=2as_0$

here v=0

u=12 m/s

$a=9.8 m/s^2$

$0-12^2=2(-9.8)(s)$

$s_0=\frac{144}{2\times 9.8}=7.34 m$

$s+s_0=36+7.34=43.34 m$

7 0

3 years ago