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zmey [24]
3 years ago
14

Two piles of heavy boxes must be lifted onto a shelf. Each pile has 20 boxes and each box is the same size and weight. Tom and c

laudia are each responsible for a pile. Tom lifts each box straight up from the pile to the shelf. Claudia places a long gradual ramp that leads from pile to the shelf. She pushes each box up the ramp until it rests on the shelf. Who used more force
Physics
2 answers:
Murrr4er [49]3 years ago
4 0
Tom used more Force but over a shorter distance. Tom and Claudia both did the same amount of work.
Alex787 [66]3 years ago
4 0

In this scenario, we can tell that Tom used more force.


We can tell this is correct because Tom did not use any shortcuts like Claudia did. Claudia placed her heavy box on a ramp that then transferred her box to where the shelves are. After that, all she had to is put the box on the shelf.



- Marlon Nunez

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7 0
3 years ago
A snowboarder on a slope starts from rest and reaches a speed of 4.2 m/s after 7.3 s
Yakvenalex [24]

The car's acceleration will be 0.575 m/s².The unit of acceleration is m/sec².

<h3>What is acceleration?</h3>

The rate of velocity change concerning time is known as acceleration.

Given data;

Initial velocity, u= 0 m/s

Final velocity, v= 4.2 m/s

Time elapsed, t = 7.3 seconds.

To find ;

Acceleration, a

The acceleration when the change in velocity is observed by the formula as:

a= (v-u)/(t)

Substitute the given values:

a= (4.2-0)/(7.3)

a=(4.2)/(7.3)

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To learn more about acceleration, refer to the link brainly.com/question/2437624

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3 0
2 years ago
What is the electric field strength between two parallel plates 5cm apart with a potential difference of 25V across them?
Butoxors [25]

Use the following formula for the electric field strength between two parallel plates:

E = V/d

where,

V: potential difference = 25V

d: distance between plates = 5 cm = 0.05 m

Replace the previous values of the parameters into the formula for E:

E=\frac{25V}{0.05m}=500\frac{V}{m}

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5 0
1 year ago
Two plates of area 30.0 cm^2 are separated by a distance of 0.0590 cm. If a charge separation of 0.0240 μC is placed on the two
topjm [15]

Answer:

V=533.33 V

Explanation:

 Given that

A= 30 cm²

d= 0.059 cm

Q= 0.0240 μ C

We know that capacitance given as

C=\dfrac{\varepsilon _oA}{d}

Now by putting the values

C=\dfrac{8.85\times 10^{-12}\times 30\times 10^{-4}}{0.059\times 10^{-2}}

C=4.5\times 10^{-11}\ F

Voltage difference given as

Q= V .C

V=Q/C

V=\dfrac{0.0240\times 10^{-6}} {4.5\times 10^{-11}}

V=533.33 V

3 0
3 years ago
A ball player catches a ball 3.24 s after throwing it vertically upward.With what speed did he throw it?
Firdavs [7]
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8 0
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