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UNO [17]
3 years ago
8

Which one of the following questions about animals called affairs, pictured above, is the scientific question?

Chemistry
1 answer:
tino4ka555 [31]3 years ago
3 0

The answer is B...

because any of the others could have an opinion based answer but B will always be the same its a fact not opinion.

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D=___g/mL<br> v=100mL<br> m=1.5kg=___g
Bess [88]

The volume is 100mL.

The mass is 1.5kg which is equal to 1500g.

Thus, the density is 1500g / 100mL which is 15g/mL.

8 0
3 years ago
For the reaction, Cl2 + 2KBr --&gt; 2KCl + Br2, how many moles of potassium chloride, KCl, are produced from 102g of potassium b
Sedaia [141]

Solution :

From the balanced chemical equation, we can say that 1 moles of KBr will produce 1 moles of KCl .

Moles of KBr in 102 g of potassium bromide.

n = 102/119.002

n = 0.86 mole.

So, number of miles of KCl produced are also 0.86 mole.

Mass of KCl produced :

m = 0.86 \times Molar \  mass \ of \  KCl\\\\m = 0.86 \times 74.5 \ gram \\\\m = 64.07\  gram

Hence, this is the required solution.

5 0
3 years ago
Well, we might as well try a similar question. Magnesium metal reacts with hydrochloric acid to produce hydrogen gas and an aque
Andrei [34K]

Answer: Magnesium Mg

Explanation:

Oxidization is the process by which a substance either gains oxygen or losses electrons.

The chemical reaction of the above is denoted by,

Mg(s) + 2HCl(aq) -----> MgCl2(aq) + H2(g)

Mg went from a 0 to a +2 state which would mean that it lost electrons.

It was therefore oxidized.

Please do react or comment if you need clarification or if the answer helped you. This can help other users as well. Thank you.

5 0
3 years ago
How many grams of propanol (C3H7OH, 60.10 g/mol) would be needed to make 750 mL of a solution with an osmotic pressure of 25 atm
Ierofanga [76]
Answer:

= 46.06 grams

Explanation:

P=cRT

25 = c (0.0821)(298)

concentration = c = 1.021 M

number of moles = (1.021)(0.75) = 0.7664 moles

mass = (0.7664)(60.10)=40.06 grams
3 0
2 years ago
(2pts) During the Purification of Lactate Dehydrogenase (LDH) experiment, you will need 50ml of buffer A150. Buffer A150 is 30mM
torisob [31]

Answer:

The answer is "20 \ mL"

Explanation:

Given:

Molarity= number of moles

because it is 1 Liter

\to \frac{0.03\ moles}{1.5 moles}=0.02\ L= 20 \ mL \ of\  Tris\\\\

therefore,

it takes 20 mL of Tris.

\to \frac{0.150 \ moles}{5\ moles} =0.03\ L\\\\

                     = 30 \ mL \ of\ Nacl

So, take 20 \ mL\ of\ NaCl.

6 0
3 years ago
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