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chubhunter [2.5K]
3 years ago
13

How do earths magnetic pole reversals provide evidence for plate tectonics

Physics
2 answers:
Alinara [238K]3 years ago
6 0
Rocks get older as you move away from the water surface
lianna [129]3 years ago
5 0

Answer:

Explanation:

As per the concept of plate tectonics, The continents are like rock plates moving on the magma underneath it and magnetism is a part of it.

As we know Earth spin on its axis, this interaction of Earth's spin and magnetic material inside the Earth creates a magnetic field from North to South pole.

When hot material inside the Earth cool, it solidify and the magnetic material form crystals which align themselves along the Earth's magnetic field.

Hence by this way Earth's magnetic pole reversal provide evidence for plate tectonics.

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ludmilkaskok [199]

Answer:

from Late Latin convectionem

Explanation:

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What is the cell theory?
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Cell theory is a scientific theory which describes the properties of cells. These cells are the basic unit of structure in all organisms and also the basic unit of reproduction.
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A 3-ft3 rigid tank initially contains saturated water vapor at 300°F. The tank is connected by a valve to a supply line that car
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Explanation:

Given\\V=3ft^3\\T_{1} =300^oF\\T_{L} =400^oF\\P_{L} =200psia\\V_{f} =0.5V

We assume kinetic and potential energy changes are negligible and there is no work interactions.

a) Taking tank as a system, The energy balance can be define as

E_{in}- E_{out}= E_{sys}

m_{i} h_{L} -Q_{out}=m_{2}  u_{2}-m_{1}  u_{1}

The mass balance could be written as

m_{in}- m_{out}= m_{sys} \\m_{i}= m_{2}- m_{1}

The final pressure in the tank could be defined as following

P_{2} =P_{sat300^oF}

from standard steam table we know at

T_{2}= T_{1}=300^oF\\ P_{2}=67.028psia

b)

From steam table at

T_{1} =300^oF\\v_{1}= v_{g}=6.4663ft^3/lbm\\v_{1}=  v_{g}=1099.8Btu/lbm\\ v_{f} =0.01745ft^3/lbm\\v_{f} =269.51Btu/lbm\\

at\\P_{L} =200psia\\T_{L}=400^oF\\h_{L}=1210.9Btu/lbm

initial mass in the tank could be define as

m_{1}=\frac{V}{v_{1} }  \\m_{1} =\frac{3}{6.4663} =0.464lbm\\

Final mass in the tank could be define as

m_{2}=\frac{V_{f} }{v_{f} }+\frac{V_{g} }{v_{g} }  \\ m_{2} =\frac{1.5}{0.01745} +\frac{1.5}{6.4663} =86.2lbm

The amount of steam that has entered the tank

m_{i}=m_{2}-  m_{1}\\ m_{i}=86.2-0.464=85.74lbm

c)

The internal energy in final state could be defined as following

U_{2}=m_{f}  u_{f}+ m_{g} u_{g}\\ U_{2} =85.96*269.51+0.232*1099.8=23422Btu\\

The heat transfer could be defined as following

Q_{out}=m_{i}  h_{L}+m_{1}  u_{1}-m_{2}  u_{2}\\ Q_{out}=85.74*1210.9+0.464*1099.8-23422=80910Btu

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A crate is being pulled down an incline as shown in the figure. With respect to the crate's direction of motion, which of the fo
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