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4 years ago

Risk-assessment models are used to _____.

Physics

2 answers:

pentagon [3]4 years ago

8 0

<span>The answer is develop policies</span>

labwork [276]4 years ago

3 0

Answer:

Design quality and security procediments.

Explanation:

The risk -assessment models are a powerful tool to prevent accidents or incidents in the Industry.

For example in the Oil and Gas Industry is usually to celebrate a HAZOP meeting between all engineering disciplines involved to discuss the position for example of all equipments of plant. Each equipment has an impact at the area where it was installed in case of a fail.

There are commercial software to simulate the radiation of each equipment in a plant of gas.

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Un avión de rescate en Alaska deja caer un paquete de provisiones a un grupo de exploradores extraviados. Si el avión viaja hori

posledela

Answer:

180.4 m

Explanation:

The package in relation to the point where it was released falls a certain distance that is calculated by applying the horizontal motion formulas , as the horizontal speed of the plane and the height above the ground are known, the time that It takes the package to reach its destination and then the horizontal distance (x) is calculated from where it was dropped, as follows:

$V_{ox}=v_x = 40 \ m/s$

h = 100 m

x =?

Height formula h:

$h=g \times \frac{t^2}{2}$

Time t is cleared:

$t = \sqrt{\frac{2h}{g}}$

$t = \sqrt{\frac{2 \times 100}{9.8}}$

t = 4.51 sec

Horizontal distance formula x:

$x=V_x \times t$

x = 40 m / sec x 4.51 sec

x = 180.4 m

4 0

3 years ago

A positively charged particle Q1 = +35nC is held fixed at the origin. A second charge of mass m = 3.5ug is floating a distance d

cupoosta [38]

Answer:

Explanation:

Q1 = 35 nC = 35 x 10^-9 C

m = 3.5 micro gram = 3.5 x 10^-9 Kg

d = 35 cm = 0.35 m

(a) The electrostatic force between the two charges is balanced by the weight of another charge.

F = m g

$\frac{1}{4\pi \epsilon _{0}}\frac{Q_{1}Q_{2}}{d^{2}}=mg$

$Q_{2}=\frac{4\pi \epsilon _{0}mgd^{2}}{Q_{1}}$

(b) By substituting the values

$Q_{2}=\frac{3.5\times 10^{-9}\times 9.8\times 0.35\timees 0.35}{9\times 10^{9}\times 35\times 10^{9}}$

Q2 = 13.34 x 10^-12 C

Q2 = 0.0134 nC

4 0

4 years ago

You walk east for 10m then turn north 15m what is your displacementm

Doss [256]

25m north east hope this helps

5 0

3 years ago

The winch takes in cable at the constant rate of 130 mm/s. if the cylinder mass is 115 kg, determine the tension in cable 1. neg

nikitadnepr [17]

By applying Newton's second law of motion;

ma = mg - T

Where,
m = mass; a = downward accelerations (+ve value) or upward acceleration (-ve value); g = gravitational acceleration; T = tension.

For the current case, the velocity is constant therefore,
a = 0

Then,
0 = mg - T
T = mg = 115*9.81 = 1128.15 N

Tension in the cable is 1128.15 N.

8 0

3 years ago

A 100 V battery is connected across a

Sergio039 [100]

1 mA = 0.001 A

Therefore, 5 mA = 0.001 * 5

=0.005 A

Resistance = voltage / current

= 100 / 0.005

= 20000 ohms

Current = voltage / resistance

= 25 / 20000

= 0.00125 A (or) 1.25 mA

5 0

3 years ago