In a transformer, energy is carried from the primary coil to the secondary coil by magnetic field in the iron core.
To find the answer, we have to know more about the transformer.
<h3>
How transformer works?</h3>
- An item utilized in the transfer of electric energy is a transformer.
- AC current is used for transmission.
- It is frequently used to modify the supply voltage between circuits without altering the AC frequency.
- The fundamentals of mutual and electromagnetic induction govern how the transformer operates.
- Magnetic field through the primary coil changes when primary coil current varies. the iron core of the secondary coil likewise has a magnetic field.
- EMF is therefore generated in the secondary coil.
Thus, we can conclude that, in a transformer, energy is carried from the primary coil to the secondary coil by magnetic field in the iron core.
Learn more about the transformer here:
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Answer:

Explanation:
We are given that
Mass of glass,

Volume,
Mass of water=
Density of water=
Temperature of hot water,
Specific heat of glass,
Specific heat of water,







Distance, since distance represents how far something has travelled, which would be in our case 2.5m.
Answer:
The acceleration of the both masses is 0.0244 m/s².
Explanation:
Given that,
Mass of one block = 602.0 g
Mass of other block = 717.0 g
Radius = 1.70 cm
Height = 60.6 cm
Time = 7.00 s
Suppose we find the magnitude of the acceleration of the 602.0-g block
We need to calculate the acceleration
Using equation of motion

Where, s = distance
t = time
a = acceleration
Put the value into the formula



Hence, The acceleration of the both masses is 0.0244 m/s².
Answer:
A. the pressure decrease
Explanation:
pressure decreases when the surface area over which a force is applied increases. pressure increases when the surface area over which force is applied decreases.