Answer:
K.E = 5.53 eV = 8.85 x 10⁻¹⁹ J
Explanation:
First we calculate the energy of photon:
E = hc/λ
where,
E = Energy of Photon = ?
h = Plank's Constant = 6.626 x 10⁻³⁴ J.s
c = speed of light = 3 x 10⁸ m/s
λ = wavelength = 120 nm = 1.2 x 10⁻⁷ m
Therefore,
E = (6.626 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/(1.2 x 10⁻⁷ m)
E = (16.565 x 10⁻¹⁹ J)(1 eV/1.6 x 10⁻¹⁹ J)
E = 10.35 eV
Now, from Einstein's Photoelectric equation we know that:
Energy of Photon = Work Function + K.E of Electron
10.35 eV = 4.82 eV + K.E
K.E = 10.35 eV - 4.82 eV
<u>K.E = 5.53 eV = 8.85 x 10⁻¹⁹ J</u>
Answer:
Explanation:
is the magnetic quantum number.
The only possible value for the magnetic quantum number for an electron in an s orbital is 0.
The first three quantun numbers are:
- n: principal quantum number. It may have positive integer values: 1, 2, 3, 4,5, 6, 7, ...
: Azimuthal or angular momentum quantum number. It may have integer values from 0 to n - 1.
This quantum number is related to the type (or shape) of the orbital:
For s orbitals 
For p orbitals 
For d orbitals 
For f orbitals 
In this case, it is an s orbital, so we have .
- , the third quantum number can have integer values
to 
Since, for the s orbitals , the only possible value for 
is zero.
For example, a trade secret may<span> be a confidential device, pattern, </span>information<span>, or </span>chemical<span> make-up.</span>Chemical industry<span> trade secrets are generally formulas, process data, or a "specific </span>chemical<span> identity." The latter is the type of trade secret </span>information<span> referred to in the Hazard Communication Standard. The term includes</span>
2 times 10 to the power of 5 is your answer.
