Answer:
V = 26.95 cm³
Explanation:
Density is given by the formula :
ρ = m÷V
Density = mass ÷ Volume
Given both density and mass we rearrange, substitute and solve for Volume :
Rearranging the equation to make Volume the subject :
ρ = m÷V
ρV = m
V = m÷ ρ
Now substitute :
V = 45 ÷ 1.67
V = 26.9461077844
Take 2 decimal places as the density is 2 decimal places :
V = 26.95
Units will be cm³ as it is volume
Hope this helped and have a good day
Thank you for posting your question here at brainly. Below is the solution. I hope the answer will help.
<span>Cl^- 1s^2 2s^2p^6 3s^2 3p^6 1s^2 2s^2p^6 S = 10; 3s^2 3p^6 S = 0 </span>
<span>Zeff = Z-S = 17- 10 =7 </span>
<span>K^+ 1s^2 2s^2p^6 3s^2 3p^6; 1s^2 2s^2p^6 S = 10; 3s^2 3p^6 S = 0 </span>
<span>Zeff = Z-S = 19- 10 = 9
</span>
S = 2 + 6.8 + 2.45 = 11.25
<span>Zeff(Cl^-) = 17 – 11.25 = 5.75 </span>
<span>K^+ 1s^2 2s^2p^6 3s^2 3p^6 same S as for Cl^- but Z increases by 2 hence </span>
<span>Zeff(K^+) = 19 - 11.25 = 7.75</span>
Explanation:
Charges,![q_1=8\ \mu C=8\times 10^{-6}\ C](https://tex.z-dn.net/?f=q_1%3D8%5C%20%5Cmu%20C%3D8%5Ctimes%2010%5E%7B-6%7D%5C%20C)
![q_2=-5\ \mu C=-5\times 10^{-6}\ C](https://tex.z-dn.net/?f=q_2%3D-5%5C%20%5Cmu%20C%3D-5%5Ctimes%2010%5E%7B-6%7D%5C%20C)
The distance between charges, r = 10 cm = 0.1 m
We need to find the magnitude and direction of the electric force. It is given by :
![F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times 8\times 10^{-6}\times 5\times 10^{-6}}{(0.1)^2}\\\\F=36\ N](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7Bkq_1q_2%7D%7Br%5E2%7D%5C%5C%5C%5CF%3D%5Cdfrac%7B9%5Ctimes%2010%5E9%5Ctimes%208%5Ctimes%2010%5E%7B-6%7D%5Ctimes%205%5Ctimes%2010%5E%7B-6%7D%7D%7B%280.1%29%5E2%7D%5C%5C%5C%5CF%3D36%5C%20N)
So, the required force between charges is 36 N and it is towards positive charge i.e. +8 μC.
If I can't open the lid of a jelly jar, I'd keep trying and if I can't open the lid of a jelly jar after the MANY tries I took, I'd ask for help.