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ikadub [295]
3 years ago
5

(TCO A) Explain how computer-aided design and flexible manufacturing help create small niches in the market place. Provide and e

xample of how a market with different niches might be served.
Engineering
1 answer:
polet [3.4K]3 years ago
6 0

Answer:

Explanation:

Computer aided design as well as flexible manufacturing assists in creating small niches in market place, this is done because it gives room for organizations to produce different variety of their product in numbers. This implies that organizations can streamline their offers towards small niches in the market place.

For example if in 2012 Yamaha gave 16 passengers motorcycles within the Yamaha product line. Yamaha will also offer different models of this product with each having different features and prices.

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The pressure distribution over a section of a two-dimensional wing at 4 degrees of incidence may be approximated as follows: Upp
Ilya [14]

Answer:

The lift coefficient is 0.3192 while that of the moment about the leading edge is-0.1306.

Explanation:

The Upper Surface Cp is given as

Cp_u=-0.8 *0.6 +0.1 \int\limits^1_{0.6} \, dx =-0.8*0.6+0.4*0.1

The Lower Surface Cp is given as

Cp_l=-0.4 *0.6 +0.1 \int\limits^1_{0.6} \, dx =-0.4*0.6+0.4*0.1

The difference of the Cp over the airfoil is given as

\Delta Cp=Cp_l-Cp_u\\\Delta Cp=-0.4*0.6+0.4*0.1-(-0.8*0.6-0.4*0.1)\\\Delta Cp=-0.4*0.6+0.4*0.1+0.8*0.6+0.4*0.1\\\Delta Cp=0.4*0.6+0.4*0.2\\\Delta Cp=0.32

Now the Lift Coefficient is given as

C_L=\Delta C_p cos(\alpha_i)\\C_L=0.32\times cos(4*\frac{\pi}{180})\\C_L=0.3192

Now the coefficient of moment about the leading edge is given as

C_M=-0.3*0.4*0.6-(0.6+\dfrac{0.4}{3})*0.2*0.4\\C_M=-0.1306

So the lift coefficient is 0.3192 while that of the moment about the leading edge is-0.1306.

8 0
3 years ago
1) Pareto charts are used to: A) identify inspection points in a process. B) outline production schedules. C) organize errors, p
zloy xaker [14]

Answer:

E) Please see below as the answer is self -explanatory.

Explanation:

The pareto chart, is used in quality control, and is a combined type of graph, that uses a line-type curve to denote the cumulative percentages of the different types of defects found in a sample (so the maximum value is 100%)

Also, it features a bar chart, which shows the relative occurrence of the different values (as in a histogram) which allows to find easily which defects are more relevant ones, alerting in this way about unacceptable deviations in the manufacturing process (if we are producing a good under given quality standards, for instance).

4 0
3 years ago
In a wind-turbine, the generator in the nacelle is rated at 690 V and 2.3 MW. It operates at a power factor of 0.85 (lagging) at
Juli2301 [7.4K]

To solve this problem we will apply the concepts related to real power in 3 phases, which is defined as the product between the phase voltage, the phase current and the power factor (Specifically given by the cosine of the phase angle). First we will find the phase voltage from the given voltage and proceed to find the current by clearing it from the previously mentioned formula. Our values are

V = 690V

P_{real} = 2.3MW

Real power in 3 phase

P_{real} = 3V_{ph}I_{ph} Cos\theta

Now the Phase Voltage is,

V_{ph} = \frac{V}{\sqrt{3}}

V_{ph} = \frac{690}{\sqrt{3}}

V_{ph} = 398.37V

The current phase would be,

P_{real} = 3V_{ph}I_{ph} Cos\theta

Rearranging,

I_{ph}=\frac{P_{real}}{3V_{ph}Cos\theta}

Replacing,

I_{ph}=\frac{2.3MW}{3( 398.37V)(0.85)}

I_{ph}= 2.26kA/phase

Therefore the current per phase is 2.26kA

6 0
3 years ago
Consider flow in between two parallel plates located a distance H from each other. Fluid flow is driven by the bottom plate movi
katrin2010 [14]
Wow I don’t
Know but I would
Help you
8 0
3 years ago
The complete stress distribution obtained by superposing the stresses produced by an axial force and a bending moment is correct
Zanzabum

The complete stress distribution obtained by superposing the stresses produced by an axial force and a bending moment is correctly represented by F/A - (My)/(Iz).

<h3>What is the distribution of pressure at some stage in bending?</h3>

Compressive and tensile forces expand withinside the path of the beam axis beneath neath bending loads. These forces set off stresses at the beam. The most compressive pressure is observed on the uppermost fringe of the beam whilst the most tensile pressure is positioned on the decrease fringe of the beam.

The bending pressure is computed for the rail through the equation Sb = Mc/I, wherein Sb is the bending pressure in kilos in keeping with rectangular inch, M is the most bending second in pound-inches, I is the instant of inertia of the rail in (inches)4, and c is the space in inches from the bottom of rail to its impartial axis.

Read more about beam;

brainly.com/question/25329636

#SPJ1

7 0
2 years ago
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