Answer: 383.22K
Explanation:
L = 3m, w = 1.5m
Area A = 3 x 1.5 = 4.5m2
Q' = 750W/m2 (heat from sun) ,
& = 0.87
Q = &Q' = 0. 87x750 = 652.5W/m2
E = QA = 652.5 x 4.5 = 2936.25W
T(sur) = 300K, T(panel) = ?
Using E = §€A(T^4(panel) - T^4(sur))
§ = Stefan constant = 5.7x10^-8
€ = emmisivity = 0.85
2936.25 = 5.7x10^-8 x 0.85 x 4.5 x (T^4(panel) - 300^4)
T(panel) = 383.22K
See image for further details.
Effect of Ocean currents on the Coastal regions are described below.
Explanation:
1.Ocean currents effects the temperature of the region they travel through. Warm currents increase the temperature of the coasts along which they move. Sea breezes that blow over warm currents get warmed in turn and absorb moisture. Then they carry the warmth and moisture to neighboring coastal areas.
2.When land borders the ocean, the currents of the ocean warm or cool it, depending on the nature of the particular current that flows by that land. In cases where a warm current flows along a particular coast, that coastal area will generally be warmer than it would otherwise be if it were landlocked.
3.They produce high and low tides along coastal regions.They move vertically pushing warm water and nutrients to the surface along coastal regions.
4.The circumpolar current merges the waters of the Atlantic, Indian, and Pacific Oceans and carries up to 150 times the volume of water flowing in all of the world's rivers.
Answer:
0.029N
Explanation:
Pressure = displacement × density of steel × acceleration due to gravity
displacement = 0.1in = 0.1×0.0254m = 0.00254m, density of steel = 7900kg/m^3, acceleration due to gravity = 9.8m/s^2
Pressure = 0.00254×7900×9.8 = 196.65N/m^2
Force(P) = pressure × area
Area of 1 pin-connected A-36 steel member = 0.75in^2 = 4.84×10^-6m^2
Area of 3 pin-connected A-36 steel member = 3×4.84×10^-6 = 1.452×10^-5m^2
Force(P) = 196.65 × 1.4652×10^-5 = 0.0029N
