A long chain of hydrocarbon bonded to COOH is a FATTY acid.
The HCl added = 1.25 moles
and the moles of Na2HPO4 = 1 mole
Now when acid is added in the given solution of Na2HPO4
One mole of H+ will react with one mole of Na2HPO4 to given one mole of NaH2PO4
Na2HPO4 + H+ ---> NaH2PO4
Now this one mole formed NaH2PO4 will further react with 0.25 moles of H+ left to form 0.25 moles of H3PO4 and 0.75 moles of NaH2PO4 will remain in the solution
So this will result into formation of a buffer of phosphoric acid and NaH2PO4
NaH2PO4 + H+ ---> H3PO4
pKa of H3PO4 = 2.1
so pH = pKa + log [salt] / [acid] = 2.1 + log [0.75 / 0.25] = 2.58
so the pH will be in between 2.1 to 7.2
Analiza Z drugiej zasady Newtona przyłożona siła wynosi 1 N F = ma = m (6 g) = (90 kg) (6x9,81 m / s) 5297 N I kg m / s?
Ruler is the answer of this question
Zero degree celcius = 273.15 degree kelvin
Simply, to get the value of 45.1 degree celcius in kelvin, we will add 273.15 to the given value (45.1).
Degree in kelvin = 45.1 + 273.15 = 318.25 degree kelvin
Approximating to the nearest tenth, the value will be 318.3 degree kelvin