Question

J. A gas has a volume of 12 L at 200°C with 6.0 atm.

Answer 1

Answer:

$0.4 \:$

Explanation:

I only know this answer hope it will help you if it's wrong I am sorry:(

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Answer 2

Gay Lussac's Law

$\tt \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}$

Convert:

200°C = 200 + 273 = 473 K

50°C = 50 + 273 = 323 K

Input the value:

$\tt \dfrac{6}{473}=\dfrac{P_2}{323}\\\\P_2=4.097~atm$