The value of the activation energy of an uncatalyzed reaction is greater than that of a catalyzed reaction. As we know, a catalyst provides an alternative path for the reaction to happen at a faster rate. So, for a catalyzed reactio, activation energy is lesser than the original path.
Answer:
1 : 2
Explanation:
From the question given, we obtained the following information:
T1 = 287°C = 287 +273 = 560K
T1 = 587°C = 587 +273 =860K
V1 = V
V2 =?
V1 /T1 = V2 /T2
V/560 = V2/860
Cross multiply
V2 x 560 = 860 x V
Divide both side by 560
V2 = (860 x V) / 560
V2 = 1.54V = 2V
The ratio of initial to final volume =
V1 : V2
= V : 2V
= 1 : 2
A) The answer to whether an average-size, single-family home be built with one day’s output from the saw mill is; No, it can't be built from one days output
B) The number of days will it take for the saw mill to produce enough lumber to build a neighborhood of 100 average-size homes is; 1100 days
A) From research, the average size capacity saw mill usually produces around 1500 board feet of boards per day.
Now, converting board ft to cubic meter gives;
1 board feet = 1/424 m³
Thus; 1500 board feet = 1500 * 1/424 ≈ 3.54 m³
Now, we are told that it takes 38 m³ of boards and plywood to build an average size single family home.
Since one days output = 3.54 m³
It is less than the volume required for the average sized house and so the daily output will not be sufficient.
B) Number of days to produce enough boards and plywood for the average sized family home = 38/3.54 ≈ 11 days
Thus, for 100 homes;
Number of days = 100 * 11 = 1100 days
Read more about production capacity at; brainly.com/question/25899399
Answer:
1185.0 J.
Explanation:
- The amount of heat needed to accomplish this process can be calculated using the formula:
<em>Q = m.C.ΔT</em>, where,
Q is the amount of heat needed,
m is the mass of the copper <em>(m = 47.35 g)</em>,
C is the specific heat of Cu<em> (C = 0.385 J/g.°C)</em>,
ΔT is the temperature difference (the final temperature - the initial temperature <em>(ΔT = 85.0 - 20.0 = 65.0 °C)</em>.
<em>∴ The amount of heat needed Q = m.C.ΔT </em>= (47.35 g) (0.385 J/g.°C) (65.0 °C) = 1184.933 J ≅ 1185.0 J.
Answer:
The equilibrium partial pressure of NO2 is 0.152 atm
Explanation:
Step 1: Data given
Initial pressure of NO2 = 0.500 Atm
Total pressure inside the vessel at equilibrium = 0.674 atm
Step 2: The balanced equation
2 NO2(g) ⇌ 2 NO(g) + O2(g)
Step 3: The initial pressures
pNO2 = 0.500 atm
pNO = 0 atm
pO2 = 0 atm
Step 4: The pressure at the equilibrium
pNO2 = 0.500 - 2x
pNO = 2x
pO2 = x
Total pressure = 0.674 = (0.500 - 2x) + 2x + x
0.674 = 0.500 + x
x = 0.174
pNO2 = 0.500 - 2*0.174 = 0.152 atm
pNO = 2x = 0.348 atm
pO2 = x = 0.176 atm
The equilibrium partial pressure of NO2 is 0.152 atm
