Answer:
21.6 g
Explanation:
The reaction that takes place is:
First we<u> convert the given masses of both reactants into moles</u>, using their <em>respective molar masses</em>:
- 9.6 g CH₄ ÷ 16 g/mol = 0.6 mol CH₄
- 64.9 g O₂ ÷ 32 g/mol = 2.03 mol O₂
0.6 moles of CH₄ would react completely with (2 * 0.6) 1.2 moles of O₂. As there are more O₂ moles than required, O₂ is the reactant in excess and CH₄ is the limiting reactant.
Now we <u>calculate how many moles of water are produced</u>, using the <em>number of moles of the limiting reactant</em>:
- 0.6 mol CH₄ *
= 1.2 mol H₂O
Finally we<u> convert 1.2 moles of water into grams</u>, using its <em>molar mass</em>:
- 1.2 mol * 18 g/mol = 21.6 g
Answer:
I think is the last one!!!! punnet square ⬜
Moles of Ammonia produced : 4 moles
<h3>Further explanation</h3>
Given
6 mol of H₂
Required
moles of Ammonia
Solution
Reaction
N₂ + 3H₂ → 2NH₃
In chemical equations, the reaction coefficient shows the mole ratio of the reacting compound (reactants and products)
From the equation, mol ratio of H₂ : NH₃ = 3 : 2, so mol NH₃ :
= 2/3 x moles H₂
= 2/3 x 6
= 4 moles