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4 years ago

5

Which object has the highest temperature?(see chart below)

1 answer:

pochemuha4 years ago

7 0

I can't see the chart.

But by kinetic energy theory, the temperature is a measure of the average kinetic energy of the particles.

So a low kinetic energy would depict a low temperature and a high kinetic energy would depict a high temperature.

So from this theory the particle with the highest temperature would be the one with the highest kinetic energy.

And that is by b, with a value of 1.73 x 10^5 J.

(c)object B

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A ball moving until gravity pulls it back down to the ground

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A nichrome wire and an aluminum wire, each with the same initial resistance, have the same change in resistance when heated sepa

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Answer:

The ratio of temperature change of nichrome wire to the temperature change of aluminum wire is found to be <u>9.75</u>

Explanation:

The change in resistances and initial resistances of the wires are:

Change in Resistance of Nichrome Wire = ΔR₁

Change in Resistance of Aluminum Wire = ΔR₂

Initial Resistance of Nichrome Wire = R₁

Initial Resistance of Aluminum Wire = R₂

Also, it is given that the change in resistance and initial resistance of both wires is equal. Therefore,

ΔR₁ = ΔR₂ ---------- eqn (1)

R₁ = R₂ ---------- eqn (2)

The change in Resistance due to temperature is given by formula:

ΔR = R α ΔT

Therefore, eqn (1) becomes:

R₁ α₁ ΔT₁ = R₂ α₂ ΔT₂

using eqn (2):

α₁ ΔT₁ = α₂ ΔT₂

ΔT₁/ΔT₂ = α₂/α₁

where,

α₁ = Temperature coefficient of resistance of nichrome = 0.4 x 10⁻³ °C⁻¹

α₂ = Temperature coefficient of resistance of aluminum = 3.9 x 10⁻³ °C⁻¹

Therefore,

ΔT₁/ΔT₂ = (3.9 x 10⁻³ °C⁻¹)/(0.4 x 10⁻³ °C⁻¹)

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4 years ago

1. Which object has the greatest inertia?

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4 years ago

If you unbend a paper clip made from 1.5 millimeter diameter wire and push one end against the wall, what force must you apply t

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Answer:

The force is $F = 21.48 \ N$

Explanation:

From the question we are told that

The diameter of the wire is $d = 1.5 \ mm = 1.5 *10^{-3} \ m$

The pressure is $P = 120 \ a.t.m = 120 * 101.3 *10^{3} = 12156000 Pa$

Generally the radius of the of the wire is

$r = \frac{d}{2}$

=> $r = \frac{ 1.5 *10^{-3}}{2}$

=> $r = 7.5 *10^{-4} \ m$

The Area is evaluated as

$A = \pi r^2$

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=> $A = 1.7673*10^{-6} \ m^2$

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$P = \frac{F}{A }$

=> $F = P* A$

=> $F = 12156000 * 1.767*10^{-6}$

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3 years ago