Answer:
The image height is 3.0 cm
Explanation:
Given;
object distance, = 15.0 cm
image distance, = 5.0 cm
height of the object, = 9.0 cm
height of the image, = ?
Apply lens equation;
Therefore, the image height is 3.0 cm. The negative values for image height indicate that the image is an inverted image.
Answer:
a) 2.41 km
b) 38.8°
Questions c and d are illegible.
Explanation:
We can express the displacements as vectors with origin on the point he started (0, 0).
When he traveled south he moved to (-3, 0).
When he moved east he moved to (-3, x)
The magnitude of the total displacement is found with Pythagoras theorem:
d^2 = dx^2 + dy^2
Rearranging:
dy^2 = d^2 - dx^2
The angle of the displacement vector is:
cos(a) = dx/d
a = arccos(dx/d)
a = arccos(3/3.85) = 38.8°