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GaryK [48]
1 year ago
12

A large truck is moving at 22.0 m/s. if its momentum is 125,000 kg • meters per second, what is the truck's mass? 176 kg 2750 kg

5680 kg 11,400 kg
Physics
1 answer:
solong [7]1 year ago
7 0

The  mass of the large truck is determined as 5680 kg.

<h3>Mass of the truck</h3>

The mass of the truck is calculated as follows;

P = mv

where;

  • P is momentum
  • m is mass
  • v is velocity

m = P/v

m = 125000/22

m = 5680 kg

Thus, the  mass of the large truck is determined as 5680 kg.

Learn more about momentum here: brainly.com/question/7538238

#SPJ1

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Did you diagram all the faults and folds correctly? Which fault and/or fold did you find most difficult to diagram?
butalik [34]

A fold is a stack of planar surfaces that are bent during permanent deformation and this happens when the earth's crust is compressed together.

<h3>What is a Fault?</h3>

This refers to the planar fracture that occurs in a volume of rock that causes significant displacement.

Hence, we can see that there are three types of fold and they are:

  • (1) anticlines,
  • (2) synclines  
  • (3) monoclines.

Please note that your question is incomplete so I gave a general overview of the concept to give you a better understanding.

Read more about faults and folds here:

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8 0
2 years ago
Pers
DIA [1.3K]

Answer:

2.5 cm

Explanation:

Using the relation :

Refractive index = Real Depth / Apparent depth

Refractive index = 1.6

Real depth = 4cm

Virtual depth = apparent depth = x

1.6 = 4cm / x

1.6x = 4

x = 4 / 1.6

x = 2.5

Hence, virtual depth = 2.5cm

7 0
3 years ago
What is a point of view of an object used to determine another object's motion
Finger [1]
<h2><em>A reference point is a place or object used for comparison to determine if something is in motion. An object is in motion if it changes position relative to a reference point. You assume that the reference point is stationary, or not moving.</em></h2>
7 0
3 years ago
What is the net torque on the square plate, with sides 0.2 m, from each of the three forces? F1=18 N, F2=26 N, and F3=14 N. Use
marshall27 [118]

Answer:

The net torque on the square plate is 2.72 N-m.

Explanation:

Given that,

Side = 0.2 m

Force F_{1}=18\ N

Force F_{2}=26\ N

Force F_{3}=14\ N

We need to calculate the torque due to force F₁

Using formula of torque

\tau_{1}=-F_{1}d_{1}

\tau_{1}=-F_{1}\times\dfrac{a}{2}

Put the value into the formula

\tau_{1}=-18\times\dfrac{0.2}{2}

\tau_{1}=-1.8\ N-m

We need to calculate the torque due to force F₂

Using formula of torque

\tau_{2}=F_{2}d_{2}

\tau_{2}=F_{2}\times\dfrac{a}{2}

Put the value into the formula

\tau_{2}=26\times\dfrac{0.2}{2}

\tau_{2}=2.6\ N-m

We need to calculate the torque due to force F₃

Using formula of torque

\tau_{3}=F_{3}d_{3}

\tau_{3}=(F_{3}\sin45+F_{3}\cos45)\times\dfrac{a}{2}

Put the value into the formula

\tau_{3}=0.1(14\sin45+14\cos45)

\tau_{3}=1.92\ N-m

We need to calculate the net torque on the square plate

\tau=\tau_{1}+\tau_{2}+\tau_{3}

\tau=-1.8+2.6+1.92

\tau=2.72\ N-m

Hence, The net torque on the square plate is 2.72 N-m.

3 0
3 years ago
Heat gained or lost is mass times specific heat times change in temperature.
BlackZzzverrR [31]

the answer would be B

6 0
3 years ago
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