Explanation:
The test for hydrogen consists of holding a burning splint held at the open end of a test tube of gas. If the gas is hydrogen it burns with a loud “squeaky pop” which is the result of the rapid combustion of hydrogen with oxygen to produce water.
Answer:
10.01 cm
Explanation:
Given that,
The time delay between transmission and the arrival of the reflected wave of a signal using ultrasound traveling through a piece of fat tissue was 0.13 ms.
The average propagation speed for sound in body tissue is 1540 m/s.
We need to find the depth when the reflection occur. We know that, the distance is double when transmitting and arriving. So,

or
d = 10.01 cm
So, the reflection will occur at 10.01 cm.
Hello!
First one we can use that PE=mgh so we have
4.37*10^5J/(9.12*10^3kg*9.80m/s^2)= 4.89m
Second one we can use Newton’s Second Law
F=ma and in this case F=mg so we have
g= 3.28*10^-2N/6*10^-3kg = 5.47m/s^2
Hope this helps. Any questions please ask. Thank you.
Explanation:
a) How much work is done by gravity?
- w = f x d
- w = 950 x 10 x 5.5 = 52250j
b) How much work is done by tension?
- v²=u²+2as
- 0.75²=0.25²+2a x5.5
- 0.56=0.06+2a x5.5
- 2a x5.5 = 0.56 - 0.06
- 2a x 5.5 =0.5
- 11a=0.5
- a = 0.5/11 = 0.05m/s²
w = f x d
w = 950 x 0.05 x 5.5 = 261.25j