The percent composition is defined by mass percent. So the calculation is through the atomic mass. The mass for H is 1, Cl is 35.5, O is 16. So the answer is B.
Answer:
c) FAD is the oxidizing agent
Explanation:
The β-oxidation is a catabolic process where fatty acids are degraded into a final product: Acetil-CoA. In order this process occurres, the fatty acid chain is being removed from a pair of carbon atoms on each cycle
Before the β-oxidation takes place, the fatty acid molecule should be activated, so it can go through the mitochondrial membrane into (via a carnitine translocator)
Once the activated molecule is inside the mitochondrial matrix, it can go through the β-oxidation: the first step is the oxidation of the fatty acid, with the enzyme Acyl-CoA-dehydrogenase (this enzyme catalyzes the creation of a double bond between carbon-2 and carbon-3.
This enzyme has attached a coenzyme: FAD, which takes the electrons (from the fatty acid oxidation) and becomes a reduced component: FADH2:
Acyl-CoA + FAD ↔ trans-Δ2-enoyl-CoA + FADH2
Answer:
5.0 %
Explanation:
Given data
- Volume of ethylene glycol (solute): 50 mL
- Volume of water (solvent): 950 mL
Step 1: Calculate the volume of solution
If we assume that <em>the volumes are additive</em>, the volume of the solution is equal to the sum of the volume of the solute and the solvent.
V = 50 mL + 950 mL = 1000 mL
Step 2: Calculate the percent by volume
We will use the following expression.
![\% v/v = \frac{volume\ of\ solute}{volume\ of\ solution} \times 100 \% = \frac{50mL}{1000mL} \times 100 \% = 5.0\%](https://tex.z-dn.net/?f=%5C%25%20v%2Fv%20%3D%20%5Cfrac%7Bvolume%5C%20of%5C%20solute%7D%7Bvolume%5C%20of%5C%20solution%7D%20%5Ctimes%20100%20%5C%25%20%20%3D%20%5Cfrac%7B50mL%7D%7B1000mL%7D%20%5Ctimes%20100%20%5C%25%20%3D%205.0%5C%25)
Ba: 2
Al: 3
P: 5
Se: 6
Br: 7
K: 1
Hope this helps!
Answer:
![\% H_2O=51.2\%](https://tex.z-dn.net/?f=%5C%25%20H_2O%3D51.2%5C%25)
Explanation:
Hello!
In this case, since the percent water is computed by dividing the amount of water by the total mass of the hydrate; we infer we first need the molar mass of water and that of the hydrate as shown below:
![MM_{MgSO_4* 7H_2O}=120.36 g/mol+7*18.02g/mol\\\\MM_{MgSO_4* 7H_2O}=246.5g/mol](https://tex.z-dn.net/?f=MM_%7BMgSO_4%2A%207H_2O%7D%3D120.36%20g%2Fmol%2B7%2A18.02g%2Fmol%5C%5C%5C%5CMM_%7BMgSO_4%2A%207H_2O%7D%3D246.5g%2Fmol)
Thus, the percent water is:
![\% H_2O=\frac{7*MM_{H_2O}}{MM_{MgSO_4* 7H_2O}} *100\%\\\\](https://tex.z-dn.net/?f=%5C%25%20H_2O%3D%5Cfrac%7B7%2AMM_%7BH_2O%7D%7D%7BMM_%7BMgSO_4%2A%207H_2O%7D%7D%20%2A100%5C%25%5C%5C%5C%5C)
So we plug in to obtain:
![\% H_2O=\frac{7*18.02}{246.5} *100\%\\\\\% H_2O=51.2\%](https://tex.z-dn.net/?f=%5C%25%20H_2O%3D%5Cfrac%7B7%2A18.02%7D%7B246.5%7D%20%2A100%5C%25%5C%5C%5C%5C%5C%25%20H_2O%3D51.2%5C%25)
Best regards!