Balanced equation for hydrogen gas is passed over powdered iron(III) oxide, iron metal and water vapor form.
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<h3>What is a balanced equation?</h3>
A balanced chemical equation is a chemist's shortcut for representing the molecules and atoms involved in a chemical process using chemical symbols. On the left side of the equation are the reactants, and on the right are the products. The number of molecules involved is indicated by the coefficients, and the number of atoms in each molecule is indicated by the subscripts.
Based on the interactions of the constituent chemicals, knowledge of the law of conservation of mass, and practise with a few example equations, chemical equations can be "balanced," much like algebraic equations.
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Answer:
Explanation:
Here we have to use stoichiometry.
First of all, we have to calculate the mass of 100% of yield:
1.7 g ------- 98%
X -------- 100%
X = 1.73 g (approximately)
Second, we have to calculate the mass of N2 that is necessary to react to produce the mass of 1.73g of NH3. To do that, we have to use the Molar mass of N2 and NH3 and don't forget the stoichiometric relationship between them.
Molar Mass N2 : 14x2 = 28 g/mol
Molar Mass NH3: 14 + 3 = 17 g/mol
28g (N2) ------- 17x2 (NH3)
X ------------ 1.73 g
X = 1.42 g (approximately)
Answer:
Na2O+H2O=2NaOH
Step by step exp.
Given:
Equation Na2O+H2O=NaOH
To find: Balance the equation
Solution:
Taking LHS of the equation
LHS=Na2O+H2O
There is 2 sodium, 2 oxygen,& 2 hydrogen
To balance the equation we have equal number of atom so we multply 2 to the RHS=2NaOH
There fore the equation form is
Na2O+H2O=2NaOH
The atomic molar mass of C is 12 and of H is 1. Hence the mass ratio of H to the molecule is 8/(8+36) = 2/11
Since 50*2/11 ≈ 9, the answer is<u><em> B.</em></u>
Answer:
See explanation and image attached
Explanation:
The acid-catalyzed hydrolysis of a nitrile to give a carboxylic acid occurs by initial protonation of the nitrogen atom. This step is shown in the image attached.
The next step is the nucleophilic addition of water. The task is to show the movement of electrons in this step of the reaction mechanism. This was clearly shown in the image attached to this answer.
