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yaroslaw [1]
4 years ago
9

The amplitude of a sound is the A. frequency of the sound. B. magnitude of displacement of a sound pressure wave. C. psychologic

al aspect of sound related to frequency. D. amount of sound energy falling on a unit area. E. pitch.
Physics
2 answers:
AlladinOne [14]4 years ago
6 0

Answer:

Option B. magnitude of displacement of a sound pressure wave

Explanation:

Amplitude is simply the maximum displacement of a wave from its mean position.

Yuliya22 [10]4 years ago
6 0

Answer:

B. magnitude of displacement of a sound pressure wave.

Explanation:

In physics, amplitude means the maximum displacement attained by a particle from a particular position. The particle could be a wave or an object. When such particle reaches its peak during displacement, we say such particle has attained its amplitude. An example of such particle is the sound wave.

The amplitude of a sound is a measure of the loudness of the sound. In other words, a higher amplitude means a louder sound and vice-versa.

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A car traveling 91 km/h is 280 m behind a truck traveling 76 km/h.
Olegator [25]

Answer:

speed of car = 95 km/h

speed of truck = 75 km/h

relative speed of car with respect to truck = 95 - 75 = 20 km/h

now we will convert it into m/s

now time to cross the truck will be given as

time = 19.8 s

so it will take 19.8 s to cross the truck

Explanation:

6 0
3 years ago
Please Help!!! An engine takes 3,000 J from a hot reservoir and expels 2,400 J to a cold reservoir. What is the thermal efficien
Murljashka [212]

Answer:

80%

Explanation:

Thermal efficiency is a measure of the extent to which a heat engine is able to convert to other form. It is measure in percentage.

Thermal efficiency = \frac{E_{out} }{E_{in} } × 100%

Where E_{in} is the input energy and E_{out} is the output energy.

Given that: E_{in} = 2400 J and  E_{out} = 3000 J, therefore:

Thermal efficiency = \frac{2400}{3000} × 100%

                               = 80%

The thermal efficiency of the engine is 80%.

4 0
4 years ago
What is a stream’s discharge rate if it has a width of 10 meters, a depth of 2 meters, and a velocity of 2 meters per second?
julia-pushkina [17]

A stream’s discharge rate if it has a width of 10 meters, a depth of 2 meters, and a velocity of 2 meters per second will be 40 m^{3}/sec .

Discharge rate = velocity * area

                 = velocity * depth * width

                 = 2 * 2 * 10 = 40 m^{3}/sec

A stream’s discharge rate if it has a width of 10 meters, a depth of 2 meters, and a velocity of 2 meters per second will be 40 m^{3}/sec .

learn more about discharge rate

brainly.com/question/20709500?referrer=searchResults

#SPJ4

4 0
2 years ago
The function​ s(t) represents the position of an object at time t moving along a line. Suppose s (2 )equals 146and s (6 )equals
sineoko [7]

Answer:

v(t) = 27 units

Explanation:

The function s(t) represents the position of an object at time t moving along a line such that,

s(2)=146

and

s(6)=254

We need to find the average velocity of the object over the interval of time [2,6]. The velocity of the object is equal to the total distance divided by time. It is given by :

v(t)=\dfrac{s(6)-s(2)}{6-2}

v(t)=\dfrac{254-146}{6-2}

v(t) = 27 units

So, the  average velocity of the object is 27 units. Hence, this is the required solution.

5 0
3 years ago
2.
Afina-wow [57]

Answer:

2.76×10⁻¹⁰ C

Explanation:

Applying,

V = W/q................... Equation 1

Where V = Electric Potential, E = Electric potential energy, q = charge.

make q the subject of the equation

q = W/V................ Equation 2

From the question,

Given: W = 4.26×10⁻⁸ J, V = 154.5 V

Substitute these values into equation 2

q = 4.26×10⁻⁸/154.5

q = 2.76×10⁻¹⁰ C

3 0
3 years ago
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