Answer:
Magnetic field, B = 0.042 T
Explanation:
It is given that,
Speed of charged particle, 
Angle between velocity and the magnetic field, 
Charge, 
Magnetic force, F = 0.002 N
The magnetic force is given by :

B is the magnetic field


B = 0.042 T
So, the strength of the magnetic field is 0.042 Tesla. Hence, this is the required solution.
Answer:
s=1721.344m ,v=104.96m/s.
Explanation:
using thr equation of motion;

u=0, plane starts from rest,


s=1721.344m
v=u+at
v=0 +3.2*32.8
v=104.96m/s
Answer:
39.2m/s
Explanation:
The potential energy the book has right before it falls is equal to the kinetic energy in falling.
PE = KE
mgh = (1/2)mv
2gh=v
v=(2)(9.81)(2)
v=39.24m/s
Answer:
D = 9.9 10⁶ mi
Explanation:
In the exercise they give the expression for maximum viewing distance
D = 2 r h + h²
Ask for this distance for a height of 1100 feet
Let's calculate
D = 2 3960 1100 + 1100²
D = 8.712 10⁶ + 1.21 10⁶
D = 9.92 10⁶ mi
D = 9.9 10⁶ mi
Answer:3.33x10^(-17)
Explanation:
Period=wavelength ➗ velocity
Period=1/10^8 ➗ (3x10^8)
Period=3.33x10^(-17)