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DochEvi [55]
3 years ago
13

Q Q 3. (08.02 MC)

Chemistry
2 answers:
AnnyKZ [126]3 years ago
7 0

Answer: A volume of 455 mL from 0.550 M KBr solution can be made from 100.0 mL of 2.50 M KBr.

Explanation:

Given: V_{1} = ?,         M_{1} = 0.55 M

V_{2} = 100.0 mL,        M_{2} = 2.50 M

Formula used to calculate the volume of KBr is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula as follows.

M_{1}V_{1} = M_{2}V_{2}\\0.55 M \times V_{1} = 2.50 M \times 100.0 mL\\V_{1} = 455 mL

Thus, we can conclude that a volume of 455 mL from 0.550 M KBr solution can be made from 100.0 mL of 2.50 M KBr.

Basile [38]3 years ago
3 0

Answer:

455 milliliters (mL)

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If a buffer solution is 0.220 M in a weak acid ( Ka=7.4×10−5) and 0.540 M in its conjugate base, what is the pH?
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pH = pKa + log( [A⁻] / [HA])

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now the conjugate base of the weak acid HA is

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pKₐ = -logKₐ

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