Question

Q Q 3. (08.02 MC)

Answer 1

Answer: A volume of 455 mL from 0.550 M KBr solution can be made from 100.0 mL of 2.50 M KBr.

Explanation:

Given: $V_{1}$ = ?,         $M_{1}$ = 0.55 M

$V_{2}$ = 100.0 mL,        $M_{2}$ = 2.50 M

Formula used to calculate the volume of KBr is as follows.

$M_{1}V_{1} = M_{2}V_{2}$

Substitute the values into above formula as follows.

$M_{1}V_{1} = M_{2}V_{2}\\0.55 M \times V_{1} = 2.50 M \times 100.0 mL\\V_{1} = 455 mL$

Thus, we can conclude that a volume of 455 mL from 0.550 M KBr solution can be made from 100.0 mL of 2.50 M KBr.

Answer 2

Answer:

455 milliliters (mL)