Answer:
Explanation:
Given
Mass of monkey A=20lb
Mass of monkey B=26lb
Mass of monkey C=25lb
acceleration of monkey A=
acceleration of monkey B=0
acceleration of monkey C=
Force Due to monkey A
Force Due to monkey A
Force Due to monkey A
In addition to it Weights of monkeys will be acting downwards therefore net Downwards force is balanced by tension
T=
Answer:
58.32 N
Explanation:
Area of a circle = 

where r is the radius of the circle.
The cylinder has a radius of 0.02 m, its area is;
= 

=
x 
=
x 0.0004
= 1.2571 x 
Area of the cylinder is 0.0013
.
The safety valve has a radius of 0.0075 m, its area is;
= 

=
x 
=
x 5.625 x 
= 1.7679 x 
Area of the valve is 0.00018
.
From Hooke's law, the force on the safety valve can be determined by;
F = ke
= 950 x 0.0085
= 8.075 N
Minimum force,
, required can be determined by;
= 
= 
= 
= 58.32
The minimum force that must be exerted on the piston is 58.32 N.
From Hooke's law, the length of the spring after extension and after the mass is attached is 1.788 meters. Option B is the answer.
<h3>
HOOKE'S LAW</h3>
Hooke's law state that in an elastic material, the force applied is directly proportional to the extension provided that the elastic limit is not exceeded.
Given that a 12.0 kg mass is attached to 1.2 m long spring with a spring constant of 200.0 N/m.
The given parameters are:
- Initial length
= 1.2 m
- Spring constant K = 200 N/m
According to Hooke's law
F = Ke
But F = mg
mg = Ke
Substitute all the parameters into the formula to get extension e
12 x 9.8 = 200e
e = 117.6 / 200
e = 0.588 m
The length of the spring after extension and after the mass is attached will be
=
+ e
= 1.2 + 0.588
= 1.788 m
Therefore, the correct answer is option B because the length of the spring after extension and after the mass is attached is 1.788 meters.
Learn more about Hooke's law here: brainly.com/question/12253978
Answer:
Alternating current
Explanation:
The electrical current periodically changes direction.