Answer:
2991.47 [cm^2]
Explanation:
To solve this problem we must perform a dimensional analysis and use the corresponding conversion values:
![3.22[ft^{2}]*\frac{12^{2}in^{2} }{1^{2}ft^{2}} *\frac{2.54^{2}cm^{2} }{1^{2}in^{2} } \\2991.47[cm^{2}]](https://tex.z-dn.net/?f=3.22%5Bft%5E%7B2%7D%5D%2A%5Cfrac%7B12%5E%7B2%7Din%5E%7B2%7D%20%7D%7B1%5E%7B2%7Dft%5E%7B2%7D%7D%20%2A%5Cfrac%7B2.54%5E%7B2%7Dcm%5E%7B2%7D%20%20%7D%7B1%5E%7B2%7Din%5E%7B2%7D%20%7D%20%5C%5C2991.47%5Bcm%5E%7B2%7D%5D)
The picture isn’t clear so I can’t read the dimensions of the box but I can try my best to guide u through the question.
For part a u need to find the volume of the box as that will equal the volume of sand that can be filled inside.
For this u multiply the height, width and length of the box.
For part b the mass of sand alone will be
=Mass of box + sand - Mass of empty box
=216 - 40
=176 grams
For part c the density of sand can be calculated by the formula
Density= Mass/Volume
So the mass (176g) / volume from part a
For part d u need to know that something will float if it has a lower density than what it is floating in. If the final density of sand that was found in part c is less than the density of gold (19.3 g/cm^3) it will float. Otherwise it will sink.
Hope this helped!
Answer: D.
Explanation: Just took the quiz.
Answer:
The other angle is 120°.
Explanation:
Given that,
Angle = 60
Speed = 5.0
We need to calculate the range
Using formula of range
...(I)
The range for the other angle is
....(II)
Here, distance and speed are same
On comparing both range
Hence, The other angle is 120°
