Answer:
Explanation:
If the initial velocity is U
Then the horizontal component of the velocity is
Ux= Ucosθ
Then the range for a projectile is give as
R=Ux.t
Where t is the time of flight
The time of flight is given as
t=2USinθ/g
Therefore,
R=Ux.t
R=UCosθ.2USinθ/g
R=U^2×2SinθCosθ/g
Then, from trigonometric ratio
2SinθCosθ= Sin2θ
R=U^2Sin2θ/g
Given that θ=32° and g=9.81m/s^2
Then
R=U^2Sin2×32/9.81
R=U^2Sin64/9.81
R=0.0916U^2
Then, range is given by R=0.0916U^2
A=0.0916U^2.
T
The box is at a distance A from the point of projection. Then the range R=A
R=0.0916U^2
A=0.0916U^2
Then,
U^2=A/0.0916
U^2=10.915A
Then the initial velocity should be
U=√10.915A
U=3.3√A
<em>The first blank is </em><em>robust watermark</em>; a robust watermark will not resist tampering.
<em>The second blank is </em><em>fragile watermark</em><em>;</em> a fragile watermark will resist manipulations of the media.
<h3>What is a watermark?</h3>
A watermark is a faint design made in paper during manufacture that is visible when held against the light and clearly identifies the maker.
The watermark can be of different types depending on the application and they include:
- A robust watermark will not resist tampering.
- A fragile watermark will resist manipulations of the media.
Thus, The first blank is robust watermark; a robust watermark will not resist tampering.
The second blank is fragile watermark; a fragile watermark will resist manipulations of the media.
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Based on the information given, it can be noted that the bat was either shorter or longer than what he expected.
From the information given, it was stated that Raghu wants a cricket bat to be made by a carpenter and he tells the carpenter that the length of the bat should be 7 hand spans.
Since he got disappointed when he collected the bat, the reason for this will be because the bat was either shorter or longer than what he requested.
Learn more about length on:
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It would be helpful if you gave me a bit more information on what the cars speed is
Answer:
Diffusion requires energy only to move material through the cell membrane.
Explanation:
:)