What is the weight of a 4.2 kg bowling ball on Mars?
Answer:
1.59 kg
Explanation:
The formula is:
<u>F = G((Mm)/r2)
</u>
F is the gravitational force between two objects,
G is the Gravitational Constant (6.674×10-11 Newtons x meters2 / kilograms2),
M is the planet's mass (kg),
m is your mass (kg), and
r is the distance (m) between the centers of the two masses (the planet's radius).
Hope this helps
--Jay
What? what what what what
The way I look at these things is like this:
-- The runner covered 12 meters in 4 seconds.
Average speed = 3 meters per second.
-- Speed at the beginning = zero.
In order to make the average 3, Speed at the end = 6 meters per second.
-- Speed increased from zero to 6 meters per second in 4 seconds.
It must have increased 1.5 meters per second each second.
That's choice-#2.
If the refractive index of some substance is 1.33, then
the speed of light in that substance is
(speed of light in vacuum) / (1.33) =
(299,792,458 m/s) / (1.33) = <em>225,407,863 m/s</em>
Answer:
α = 5 10⁻³ rad / s²
Explanation:
For this exercise we can use Newton's second law for rotational movement, where the force is electric
τ = I α
Where the torque is
τ = F x r = F r sin θ
Strength is
F = q E
The moment of inertia of a small ball, which we approximate to a point is
I = m r²
We replace
2 (q E) r sin θ = 2m r² α
The number 2 is because the two forces create the same torque
α = q E sin θ
/ m r
Let's reduce the magnitudes to the SI system
m = 1.0g = 1.0 10⁻³ kg
L = 2.0 cm = 2.0 10⁻² m
q = 10 nc = 10 10⁻⁹ C
E = 1.0 10 N / C
r = L / 2
r = 1.0 10⁻² m
Let's calculate
α = 10 10⁻⁹ 1.0 10 sin 30 / 1.0 10⁻³ 1.0 10⁻²
α = 5 10⁻³ rad / s²
