Draw the lewis structure for the molecule ch3ch2cch. how many sigma and pi bonds does it contain?
1 answer:
Answer:
The structure of 1-Butyne is shown below and it contains;
Nine Sigma Bonds
Two Pi Bonds
Explanation:
In given structure the sigma bonds are highlighted with blue colour and pi bonds are highlighted by Black colour and indicated by red arrows.
Remember the very first covalent bond between two atoms is always the sigma bond. After formation of sigma bond if further p orbitals with unpaired electrons are available they will form pi bond, or two pi bonds as in given scenario.
The structure of 1-Butyne is shown below and it contains;
Nine Sigma Bonds
Two Pi Bonds
Explanation:
In given structure the sigma bonds are highlighted with blue colour and pi bonds are highlighted by Black colour and indicated by red arrows.
Remember the very first covalent bond between two atoms is always the sigma bond. After formation of sigma bond if further p orbitals with unpaired electrons are available they will form pi bond, or two pi bonds as in given scenario.
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<u><em>1.5 grams of glucose is produced from 2.20 g of CO₂.</em></u>
To find the mass of glucose produced, first you must know the balanced reaction. For this, the Law of Conservation of Matter is followed.
The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.
So, in this case, the balanced reaction is:
6 CO₂ + 6 H₂O → C₆H₁₂O₆ + 6 O₂
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the amounts of moles of each reactant and product participate in the reaction:
- CO₂: 6 moles
- H₂O: 6 moles
- C₆H₁₂O₆: 1 mole
- O₂: 6 moles
So, you know that 2.20 g of CO₂ react, whose molar weight is 44.01 g/mole. By definition of molar mass, 1 mole of CO₂ has 44.01 g. So, the number of moles that 2.20 grams of the compound represent is calculated as:
moles of CO₂= 0.05 moles
Now you must follow the following rule of three: if by stoichiometry of the reaction 6 moles of CO₂ produce 1 mole of C₆H₁₂O₆, 0.05 moles of CO₂ produce how many moles of C₆H₁₂O₆?
moles of C₆H₁₂O₆= 8.33*10⁻³
Being the molar mass of glucose 180.18 g/mole, the mass that 8.33*10⁻³ moles of the compound represent is calculated as:
<em>mass of glucose= 1.5 grams</em>
Then, <u><em>1.5 grams of glucose is produced from 2.20 g of CO₂.</em></u>