It is elastic potential energy
Answer:
Be (899 kj/mol) , Se (940.9 kj/mol), Ne(2081 kj/mol), He (2370 kj/mol),
Explanation:
For noble gases as they have complete octet so they require high amount of energy to remove the electron.
Trend along period:
As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.
Trend along group:
As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.
As the size of atom increases the ionization energy from top to bottom also decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus.
Answer:
The right response is "6 A". A further explanation is given below.
Explanation:
The given values are:
Resistance,
R = 6 ohms
Voltage,
V = 36 volts
As we know,
⇒ 
then,
⇒ 
On substituting the values, we get
⇒ 
⇒ 
Answer:
Volume O₂ at STP = 50.4 Liters
Explanation:
4Al(s) + 3O₂(g) => 2Al₂O₃(s) at STP conditions
81g Al(s) = 81g/27g/mole = 3mole Al
moles O₂ consumed = 4/3(3)moles O₂ = 2.25 moles O₂ consumed
Volume O₂ at STP = 2.25moles x 22.4L/mole = 50.4 Liters O₂
