And ironic bonds what happens to electrons? No

List three different types of chemical reactions, write the generic description, and give a brief description of each.

slava [35]

Explanation:

Combination or synthesis reaction
Decomposition or cracking reaction
Single replacement or single displacement

A combination or synthesis is a type of reaction that involves the formation of a single product from tow or more reactants:

K + J → KJ

The formation of a single compound form the union of their constituent element falls into this category of reaction.

The large and negative heat of formation is the driving force for this reaction.

A decomposition or cracking reaction is one in which two or more products are formed from a single reactant:

TK → T + K

The breaking down o a compound into its individual components like elements and other compounds falls into this category.

The driving force for this type of reaction is the high positive heat of formation and instability of the compound.

A single replacement or single displacement reaction is one in which a substance is replacing another.

TO + P → TP + O

The replacement of a metallic ion in solution by a metal atom higher in the activity series than the metal in a solution falls into this category of reaction.

learn more:

Chemical reaction brainly.com/question/6281756

#learnwithBrainly

3 0

4 years ago

Determine the empirical formula for a compound that is 70.79% carbon, 8.91% hydrogen, 4.59% nitrogen, and 15.72% oxygen. determi

IceJOKER [234]

Hello!

We use the amount in grams (mass ratio) based on the composition of the elements, see: (in 100g solution)

C: 70.79% = 70,79 g
H: 8.91% = 8.91 g
N: 4.59% = 4.59 g
O: 15.72% = 15.72 g

Let us use the above mentioned data (in g) and values will be converted to amount of substance (number of moles) by dividing by molecular mass (g / mol) each of the values, lets see:

$C: \dfrac{70.79\:\diagup\!\!\!\!\!g}{12\:\diagup\!\!\!\!\!g/mol} \approx 5.89\:mol$

$H: \dfrac{8.91\:\diagup\!\!\!\!\!g}{1\:\diagup\!\!\!\!\!g/mol} = 8.91\:mol$

$N: \dfrac{4.59\:\diagup\!\!\!\!\!g}{14\:\diagup\!\!\!\!\!g/mol} \approx 0.328\:mol$

$O: \dfrac{15.72\:\diagup\!\!\!\!\!g}{16\:\diagup\!\!\!\!\!g/mol} = 0.9825\:mol$

We note that the values found above are not integers, so let's divide these values by the smallest of them, so that the proportion is not changed, let's see:

$C: \dfrac{5.89}{0.328}\to\:\:\boxed{C\approx 18}$

$H: \dfrac{8.91}{0.328}\to\:\:\boxed{H\approx 27}$

$N: \dfrac{0.328}{0.328}\to\:\:\boxed{N\approx 1}$

$O: \dfrac{0.9825}{0.328}\to\:\:\boxed{O\approx 3}$

T<span>hus, the minimum or empirical formula found for the compound will be:

</span> $\boxed{\boxed{C_{18}H_{27}N_1O_3\:\:or\:\:C_{18}H_{27}NO_3}}\end{array}}\qquad\checkmark$

I hope this helps. =)

5 0

3 years ago

What makes a pure substance different from a heterogeneous mixture?

Vaselesa [24]

Answer: The components of a pure substance are single elements or compounds instead of a mixture of compounds.

Explanation: Pure substance consits of a pure type of particle.

All elements and compounds that are considered as pure will have fixed boiling point and melting point.

3 0

3 years ago

Read 2 more answers

The specific reaction rate of a reaction at 492k is 2.46 second inverse and at 528k 47.5 second inverse.find activation energy a

crimeas [40]

Answer:

Ea = 177x10³ J/mol

ko = $1.52x10^{19}$ J/mol

Explanation:

The specific reaction rate can be calculated by Arrhenius equation:

$k = koxe^{-Ea/RT}$

Where k0 is a constant, Ea is the activation energy, R is the gas constant, and T the temperature in Kelvin.

k depends on the temperature, so, we can divide the k of two different temperatures:

$\frac{k1}{k2} = \frac{koxe^{-Ea/RT1}}{koxe^{-Ea/RT2}}$

$\frac{k1}{k2} = e^{-Ea/RT1 + Ea/RT2}$

Applying natural logathim in both sides of the equations:

ln(k1/k2) = Ea/RT2 - Ea/RT1

ln(k1/k2) = (Ea/R)x(1/T2 - 1/T1)

R = 8.314 J/mol.K

ln(2.46/47.5) = (Ea/8.314)x(1/528 - 1/492)

ln(0.052) = (Ea/8.314)x(-1.38x $10^{-4}$

-1.67x $10^{-5}$ xEa = -2.95

Ea = 177x10³ J/mol

To find ko, we just need to substitute Ea in one of the specific reaction rate equation:

$k1 = koxe^{-Ea/RT1}$

$2.46 = koxe^{-177x10^3/8.314x492}$

$1.61x10^{-19}ko = 2.46$

ko = $1.52x10^{19}$ J/mol

3 0

3 years ago

4. When is distillation used?

Arlecino [84]

Answer:

Uses of Distillation

Distillation is used for many commercial processes, such as the production of gasoline, distilled water, xylene, alcohol, paraffin, kerosene, and many other liquids. Gas may be liquefied and separate. For example: nitrogen, oxygen, and argon are distilled from air.

3 0

3 years ago