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Answer : The molar concentration of ethanol in the undiluted cognac is 8.44 M
Explanation :
Using neutralization law,
![M_1V_1=M_2V_2](https://tex.z-dn.net/?f=M_1V_1%3DM_2V_2)
where,
= molar concentration of undiluted cognac = ?
= molar concentration of diluted cognac = 0.0844 M
= volume of undiluted cognac = 5.00 mL = 0.005 L
= volume of diluted cognac = 0.500 L
Now put all the given values in the above law, we get molar concentration of ethanol in the undiluted cognac.
![M_1\times 0.005L=0.0844M\times 0.500L](https://tex.z-dn.net/?f=M_1%5Ctimes%200.005L%3D0.0844M%5Ctimes%200.500L)
![M_1=8.44M](https://tex.z-dn.net/?f=M_1%3D8.44M)
Therefore, the molar concentration of ethanol in the undiluted cognac is 8.44 M
Explanation:
Sulfuric Acid (H2SO4) is a strong mineral acid that has is colorless when pure. This chemical is used as a chemical intermediate to manufacture other chemicals and cleaning metal surfaces. The formula for sulfuric acid is H2SO4. The molar mass of sulfuric acid is 98.07848 g mol.
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Explanation: