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3 years ago

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Which element(s) is being reduced in the redox reaction below? 6 nh4clo4 (s) + 10 al(s) 5 al2o3 (g) + 6 hcl (g) + 3 n2 (g) + 9 h

2o (g) n and al h cl o?

1 answer:

vitfil [10]3 years ago

4 0

The answer is Cl because its oxidation number goes from a +7 down to a -1.

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What is the chemical formula of diphosphorus monoxide?

Daniel [21]

Answer:

The chemical formula of diphosphorus monoxide is OP2.

I'm not sure if this is correct, but hope it helps! :)

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3 years ago

Barium reacts with a polyatomic ion to form a compound with the general formula Ba3(X)2. What would be the most likely formula f

AfilCa [17]

Answer:

D. Na₃X

Explanation:

We have the neutral compound Ba₃(X)₂. <em>The total charge (zero) is equal to the sum of the charges of the ions times the number of ions in the molecule</em>.

3 × qBa + 2 × qX = 0

3 × (+2) + 2 × qX = 0

2 × qX = -6

qX = -3

If we have the cation Na⁺ and X³⁻, a neutral molecule would require 3 Na⁺ and 1 X³⁻. The resulting compound is Na₃X.

3 0

3 years ago

Read 2 more answers

Part B Identify the sets of quantum numbers that describe all the electrons in the ground state of a neutral beryllium atom, Be.

dmitriy555 [2]

<u>Answer:</u> The set of quantum numbers for the electrons in Be atom are (2, 1, -1, 1/2), (1, 0, 0, 1/2), (1, 0, 0, -1/2) and (2, 0, 0, -1/2)

<u>Explanation:</u>

There are 4 quantum numbers:

Principal Quantum number (n) specifies the energy of the electron in a shell.
Azimuthal Quantum number (l) specifies the shape of an orbital. The value of it lies in the range of 0 to (n-1)
Magnetic Quantum number (m) specifies the orientation of the orbital in space. The value of it lies in the range of -l to +l
Spin Quantum number (s) specifies the spin of an electron in an orbital. It can either have a value of $+\frac{1}{2}$ or $-\frac{1}{2}$

Berylium (Be) is the 4th element of periodic table having electronic configuration of $1s^22s^2$

<u>For electrons in 1s-orbital, the quantum numbers can be:</u>

For first electron:

$n=1\\l=0\text{ (for s-subshell)}\\m=0\\s=+\frac{1}{2}$

For second electron:

$n=1\\l=0\\m=0\\s=-\frac{1}{2}$

<u>For electrons in 2s-orbital, the quantum numbers can be:</u>

For first electron:

$n=2\\l=0\text{ (for s-subshell)}\\m=0\\s=+\frac{1}{2}$

For second electron:

$n=2\\l=0\text{ (for s-subshell)}\\m=0\\s=-\frac{1}{2}$

Hence, the set of quantum numbers for the electrons in Be atom are (2, 1, -1, 1/2), (1, 0, 0, 1/2), (1, 0, 0, -1/2) and (2, 0, 0, -1/2)

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3 years ago

The student is now told that the four solids, in no particular order, are calcium bromide (CaBr2), sugar (C6H12O6), butanoic aci

sladkih [1.3K]

<span>Help
How did the First Great Awakening affect attitudes toward religion in the colonies during the early 1700s?</span>

5 0

3 years ago

Помогите пожалуйста или с первым вопросом или со вторым. Буду очень благодарна, т.к. это мой зачет... :С

Bess [88]

Hsiaqoanwbwiso iDisks

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3 years ago