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Alex_Xolod [135]
3 years ago
12

Is the process by which new mineral grains larger than the original mineral grains form as a result of metamorphic heat?

Chemistry
1 answer:
ExtremeBDS [4]3 years ago
5 0
Recrystallization is when new mineral grains form as a result of metarmorphic heat that are larger than the original mineral grains. 
Recrystallization is a metamorphic process that occurs under situations of intense temperature and pressure where grains, atoms or molecules of a rock or mineral are packed closer together, creating a new crystal structure. 
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The process of rocks being broken apart by physical processes is called
snow_lady [41]
T <span>The process in nature that breaks down rocks is called physical weathering.</span>
8 0
3 years ago
Read 2 more answers
NEED HELP WILL GIVE FOR BRAINLIEST PLEASE
SVEN [57.7K]

Yes. Compounds can have different properties than the elements that go into them.

EXAMPLE: water is a polar liquid, while pure hydrogen and pure oxygen are both nonpolar gasses.

8 0
4 years ago
Which of the following represents the ester functional group?
Komok [63]

Answer:

D. C=O

Explanation:

Esters are formed by the condensation of alcohols and acids with minus water. During the reaction, at least one -OH group is replaced by an O- alkyl group. The resulting compound is an ester and has a characteristic fruity smell. Its functional group is C=O

5 0
3 years ago
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A mixture of A and B is capable of being ignited only if the mole percent of A is 6 %. A mixture containing 9.0 mole% A in B flo
atroni [7]

Explanation:

As it is given that mixture (contains 9 mol % A and 91% B) and it is flowing at a rate of 800 kg/h.

Hence, calculate the molecular weight of the mixture as follows.

             Weight = 0.09 \times 16.04 + 0.91 \times 29

                          = 27.8336 g/mol

And, molar flow rate of air and mixture is calculated as follows.

                    \frac{800}{27.8336}

                     = 28.74 kmol/hr

Now, applying component balance as follows.

                0.09 \times 28.74 + 0 \times F_{B} = 0.06F_{p}

                   F_{p} = 43.11 kmol/hr

                   F_{A} + F_{B} = F_{p}

                          F_{B} = 43.11 - 28.74

                                      = 14.37 kmol/hr

So, mass flow rate of pure (B), is F_{B} = 14.37 \times 29

                                                    = 416.73 kg/hr

According to the product stream, 6 mol% A and 94 mol% B is there.

             Molecular weight of product stream = Mol. weight \times 43.11 kmol/hr

                                  = 0.06 \times 16.04 + 0.94 \times 29

                                  = 28.22 g/mol

Mass of product stream = 1216.67 kg/hr

Hence, mole of O_{2} into the product stream is as follows.

                    0.21 \times 0.94 \times 43.11

                      = 8.5099 kmol/hr \times 329 g/mol

                      = 272.31 kg/hr

Therefore, calculate the mass % of O_{2} into the stream as follows.

                 \frac{272.31}{1216.67} \times 100

                     = 22.38%

Thus, we can conclude that the required flow rate of B is 272.31 kg/hr and the percent by mass of O_{2} in the product gas is 22.38%.

4 0
3 years ago
Digoxin is available in a concentration of 0.1 mg/ml. How many ml are required to administer a 75 mcg dose?
Step2247 [10]

Answer : The volume required to administer a 75 mcg dose are, 0.75 mL

Explanation : Given,

Concentration of Digoxin = 0.1 mg/mL

That means, 0.1 mg of Digoxin present in 1 mL of solution.

Mass of dose = 75 mcg = 0.075 mg

Conversion used : (1 mcg = 0.001 mg)

Now we have to determine the volume required to administer a 75 mcg dose.

As, 0.1 mg of Digoxin required in 1 mL of solution

So, 0.075 mg of Digoxin required in \frac{0.075mg}{0.1mg}\times 1mL=0.75mL of solution

Thus, the volume required to administer a 75 mcg dose are, 0.75 mL

5 0
3 years ago
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