The equation of the energy of a photon is E=h*f.
If we increase the Planck's constant h, the energy would increase.
For example, lets double the value of Planck's constant and name it H:
H=2*h. Now lets put that into the equation for energy that we will call E₂:
E₂=H*f=2*h*f=2*E.
So we can clearly see that E₂=2*E or that if we double Planck's constant, the energy also doubles.
Answer:
31.321 rad/s
Explanation:
L = Tube length
A = Area of tube
= Density of fluid
v = Fluid velocity
m = Mass = 
Centripetal force is given by

Pressure is given by

The angular speed of the tube is 31.321 rad/s
Answer:

Explanation:
Given: The latent heat of fusion for Aluminum is 
mass to be malted m = 0.75 Kg
Energy require to melt E = mL

Therefore, energy required to melt 0.75 Kg aluminum

Answer:
N
Explanation:
Using the formula you gave:

Answer:
I think the right answer is option B.