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3 years ago

Can anyone help me on this thnxs

Physics

1 answer:

DIA [1.3K]3 years ago

8 0

Answer:

a sin Ø - b cos Ø

_______________. =

a sin Ø+ b cos Ø

=> a - b cot ∅

_____________

a + b cot ∅

=> a - b x b

______________

a + b x b

___

=> a² - b ²

__________

a ² + b²

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How is gas different from liquid?

olga_2 [115]

Answer:

Gas is different from liquid. Liquid has a definite volume but takes the shape of the container it is in. Gas on the other hand, has no definite shape or volume.

Explanation:

8 0

3 years ago

A 42.2 N force acts at 40* to the ground, causing the object to move a horizontal distance of 8.15 m. How much work was done on

slavikrds [6]

Answer:

W=F.dcos angle

w=42.2 x8.15 x cos40

w=343.93× cos 40

W=343.93 x 0.76

W=261.38 J

7 0

3 years ago

A motor transfers 12 kJ of energy in 30 s. Calculate its power.

Diano4ka-milaya [45]

Answer:

power=400Watt

Explanation:

work done =12kJ=12×10³=12000j

time taken=30s

power=?

as we know that

power=work done/time taken

power=12000J/30s

power=400Watt

i hope this will help you :)

4 0

3 years ago

Read 2 more answers

(a) An ideal gas initially at pressure p0 undergoes a free expansion until its volume is 3.80 times its initial volume. What the

trapecia [35]

Answer:

a)P/Po=0.263

b)γ=1.33 So gas is triatomic

c) $\dfrac{KE_f}{KE_i}=1.56$

Explanation:

initial pressure = Po

Initial volume = Vo

Final volume = 3.8 Vo

Lets take final pressure is P

we know that for free expansion process

PV= Constant

Po x Vo = P x 3.8 Vo

P=0.263 Po

P/Po=0.263

Now gas is compressed in adiabatic manner

Final pressure = 1.56 Po

=1.56 Po

We know that for adiabatic process

$P_1V_1^{\gamma}=P_2V_2^{\gamma}$

$\dfrac{V_2}{V_1}=\left(\dfrac{P_1}{P_2}\right)^{\dfrac{1}{\gamma}}$

$0.263P_o(3.8V_o)^{\gamma}=1.56P_o\times V_o^{\gamma}$

γ=1.33 So gas is triatomic

We know that average kinetic energy given as

$KE=\dfrac{3}{2}KT$

$\dfrac{KE_f}{KE_i}=\dfrac{T_f}{T_i}$ \

$\dfrac{KE_f}{KE_i}=\dfrac{P_fV_f}{P_iV_i}$

$\dfrac{KE_f}{KE_i}=\dfrac{1.56P_oV_o}{P_oV_o}$

$\dfrac{KE_f}{KE_i}=1.56$

3 0

3 years ago

Given: 3x + y = 1. Solve for y. y = -3 x - 1 y = -3 x + 1 y = 3 x - 1

maw [93]

Answer:

y = -3x + 1

Explanation:

Isolate the variable, y. Note the equal sign, what you do to one side, you do to the other. Subtract 3x from both sides of the equation:

3x + y = 1

3x (-3x) + y = 1 (-3x)

y = -3x + 1

y = -3x + 1 is your answer.

7 0

2 years ago

Can anyone help me on this thnxs ​

Can anyone help me on this thnxs