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vichka [17]
2 years ago
8

CHEGG A chemist requires a large amount of 1-bromo-4-phenyl-2-butene as starting material for a synthesis and decides to carry o

ut the following NBS allylic bromination reaction in the presence of UV light. Draw the structures of all of the observed products.
Chemistry
1 answer:
mylen [45]2 years ago
5 0

Answer: hello attached below is the complete question

answer :

attached below

Explanation:

Diagram of the all the observed products are attached below

note: through radical mechanism The free radicals are stabilized by resonance

Attached below

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From his experiments ,j.j Thomson concludes what?
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7 0
3 years ago
Calculate the pH at the equivalence point for the titration of 0.110 M methylamine (CH3NH2) with 0.110 M HCl. The Kb of methylam
nikklg [1K]
The reaction between the reactants would be:

CH₃NH₂ + HCl ↔ CH₃NH₃⁺ + Cl⁻

Let the conjugate acid undergo hydrolysis. Then, apply the ICE approach.

             CH₃NH₃⁺ + H₂O → H₃O⁺ + CH₃NH₂
I                0.11                       0             0
C               -x                          +x           +x
E            0.11 - x                     x             x

Ka = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]

Since the given information is Kb, let's find Ka in terms of Kb.

Ka = Kw/Kb, where Kw = 10⁻¹⁴

So,
Ka = 10⁻¹⁴/5×10⁻⁴ = 2×10⁻¹¹ = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]
2×10⁻¹¹ = [x][x]/[0.11-x]
Solving for x,
x = 1.483×10⁻⁶ = [H₃O⁺]

Since pH = -log[H₃O⁺],
pH = -log(1.483×10⁻⁶)
<em>pH = 5.83</em>


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3 years ago
Molecular compounds are capable of forming multiple covalent bonds. the compound below that contains a triple bond is:
alexira [117]

The answer is <u>CO(g).</u>

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