This question involves the concepts of equilibrium and Newton's third law of motion.
The support force will be "1 pound" for the empty bucket and the support force will be "6 pounds" after pouring water into it.
- According to the condition of equilibrium, the sum of forces acting on a stationary object must be zero. Hence, the support force of the table will be equal to the total mass of the bucket.
- According to Newton's Third Law of Motion every action force has an equal but opposite reaction force. Hence, the support force will be a reaction force to the weight of the bucket.
Therefore, the support force in each case will be equal to the total mass of the bucket:
Case 1 (empty bucket):
<u>support force = 1 pound</u>
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Case 1 (water poured):
support force = 1 pound + 5 pound
<u>support force = 6 pound</u>
<u></u>
Learn more about equilibrium here:
brainly.com/question/9076091
The rider's horizontal motion, and how much ground he covers before he hits it, have nothing to do with how long he takes to hit the ground. The problem is simply: "How long does it take an object to fall 1.12 m from rest ?"
This seems like a good time to use this formula:
Distance fallen from rest = (1/2) (acceleration) (time)²
The problem doesn't tell us what planet the skateboarder is exercising on. I'm going to assume it's on Earth, where the acceleration of gravity is 9.8 m/s². And now, here's the solution to the problem I just invented:
1.12 m = (1/2) (9.8 m/s²) (time)²
Time² = (1.12 m) / (9.8 m/s²)
Time² = 0.1143 sec²
Time = √(0.1143 sec² )
<em>Time = 0.34 second</em>
Answer:
808.25 seconds
Explanation:
From the relation,
If t = time
v = velocity
l = length
The current density, J, of a charge is given by:
Where number of charge carriers per unit volume n = 8.49 * 10²⁸
Charge of the electron, q = 1.6 * 10⁻¹⁹
Cross sectional area of the wire, A = 0.21 cm² = 0.000021 m²
Equating (1) and (2)
Since t = l/v.......(3)
Put the formula for v into equation (3)
t = 808.25 seconds
Answer:
An echo is a sound caused by the reflection of sound waves from a surface back to the listener.
Explanation:
B-thymine nucleotides is the answer i am sure